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avanturin [10]
4 years ago
14

Earth's magnetic field:

Chemistry
1 answer:
DedPeter [7]4 years ago
7 0
Does not affect solar winds
You might be interested in
Balance the equation for aluminum burning in oxygen to form aluminum oxide. ____Al + ____O2 ----> Al2o3
olchik [2.2K]

Answer:

4Al + 3O2 → 2Al2O3

Explanation:

6 0
3 years ago
Why is only one diastereomer formed in this reaction? Relate your answer to the mechanism you drew. b) If you used cis-stilbene
crimeas [40]

Answer:

1. Diastereomers have different physical properties (unlike most aspects of enantiomers) and often different chemical reactivity. ... Many conformational isomers are diastereomers as well. Diastereoselectivity is the preference for the formation of one or more than one diastereomer over the other in an organic reaction.

2. The result is a trans dibromide, as shown in the equation below

Explanation:

Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer.[1] Diasteoreomers are defined as non-mirror image non-identical stereoisomers. Hence, they occur when two or more stereoisomers of a compound have different configurations at one or more (but not all) of the equivalent (related) stereocenters and are not mirror images of each other.[2] When two diastereoisomers differ from each other at only one stereocenter they are epimers. Each stereocenter gives rise to two different configurations and thus typically increases the number of stereoisomers by a factor of two.

2. the addition of bromine to the trans and

cis isomers of 1,2-diphenylethene, more commonly known as trans- and cis-stilbene.

H

H

H H

trans-stilbene cis-stilbene

m.p. 122-124°C b.p. 82-84°C

density 0.970 g/mL density 1.011 g/mL

M.W. 180.25 g/mol M.W. 180.25 g/mol

In both cases, the nucleophilic double bond undergoes an electrophilic addition reaction

by the bromine reagent which proceeds via a cyclic bromonium ion. The addition of

bromine begins at one side of the double bond (either side is equally likely, but only one

option is drawn) and is followed by attack of bromide ion on the bromonium ion (again,

attack could occur at either carbon since the ion is symmetric, but only one option is

drawn). The result is a trans dibromide, as shown in the equation below:

Since the cis and trans isomers of stilbene have different geometries, it follows

that upon reaction with bromine they give rise to stereoisomeric bromonium ions and,

eventually, products that differ only by their stereochemistry.

4 0
4 years ago
Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate t
Alina [70]

<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.

<u>Explanation:</u>

The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

  • To calculate the total charge, we use the equation:

C=I\times t

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = 50\times 60=300s    (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

C=0.490\times 300=147C

  • To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

C = charge = 147 C

F = Faradays constant = 96500

\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol

  • Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

where,

n = number of electrons transferred = 3

Putting values in above equation, we get:

\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol

  • To calculate the mass of gallium, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Gallium = 5.077\times 10^{-4}mol

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

8 0
3 years ago
What is the concentration of a solution if 24.0 mL of H.O is needed to be added to a 100 ml solution of 6.00 M HCI?
nikdorinn [45]
The answer to this question is 40.0M
7 0
3 years ago
Alkynes are sp hybridised, alkyl halides are sp3 hybridised while alkenes are sp2 hybridised.
rodikova [14]

Answer:

True

Explanation:

superman spedierman

3 0
3 years ago
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