Students in a college statistics class want to conduct a survey to determine the percentage of students in the school who are wi
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Answer:
And the 95% confidence would be :
Step-by-step explanation:
We have the following info given from the problem
sample mean for this year
sample deviation for this year
random sample selected for this year
sample mean for last year
sample deviation for last year
random sample selected for last year
And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales
For this case the formula that we need to use is:
The degrees of freedom are given by:
The confidence level is 0.95 and the significance would be and
so then the critical value for this case is :
The margin of error would be:
And the confidence interval would be given by:
And the 95% confidence would be :