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3 years ago

I added question and example. answer it CORRECTLY and you will get brainliest!

Mathematics

1 answer:

snow_lady [41]3 years ago

5 0

Answer:

1008

Step-by-step explanation:

like the 2nd picture we split it in 3 rectangular prism

$V_{1}$ =6*7*8=336

$V_{2}$ =6*7*8=336

$V_{3}$ =6*7*8=336

V=336+336+336=1008

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The value of the 5 in the ones place in the number 5,555 is how many times as much as the value of the 5 in the hundred place?

Radda [10]

100 times, because 5 times 100 equals 500

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3 years ago

D = 8a The variable a represents the number of attendees, and the variable d represents the cost in dollars. At most how many at

suter [353]

Answer: At most 9 attendees can be there.

Step-by-step explanation:

Given equation: d = 8a , where a represents the number of attendees, and the variable d represents the cost in dollars.

To find : the number of attendees, if Will budgets a total of $72 for his graduation picnic.

72=8a

⇒ 9 = a [divide both sides by 8]

∴ a= 9

Hence, at most 9 attendees can be there.

4 0

3 years ago

Bob gets paid 64 hour heard that is 2/3 Melissa makes how much is Alicia paid per hour

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

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3 years ago

A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta

nalin [4]

Answer:

Option 2 - Approximately 24–36 pounds

Step-by-step explanation:

Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.

To find : What range of weights would 99.7% of the dogs have?

Solution :

The range of 99.7% will lie between the mean ± 3 standard deviations.

We have given,

Mean weight of Eskimo dogs is $\mu=30$

Standard deviation of Eskimo dogs is $\sigma=2$

The range of weights would 99.7% of the dogs have,

$R=\mu\pm3\sigma$

$R=30\pm3(2)$

$R=30\pm6$

$R=30+6,30-6$

$R=36,24$

Therefore, The range is approximately, 24 - 36 pounds.

So, Option 2 is correct.

5 0

4 years ago

Grace swam a mile in 21 minutes. Jill swam a mile in 19.47 minutes. How

kirill115 [55]

Answer:

1.53

Step-by-step explanation:

because 21 minus 19.47= 1.53

7 0

3 years ago

Read 2 more answers