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3 years ago

Help plzzzzzzzzzzzzzzzzzzzz

Mathematics

2 answers:

Len [333]3 years ago

7 0

What do you need help with?

Katena32 [7]3 years ago

4 0

Answer:

with what

Step-by-step explanation:

......ok.....

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What are the intercepts of y = 4x − 2?

Hitman42 [59]

Finding the intercepts is a very straight-forward process. First set y = 0 and solve the equation for x. That is your y-intercept! Then go back to the original equation and set x = 0 and solve for y. That is your x-intercept! For a linear equation like this there is only one x-intercept. For any "function" y(x) there can by definition be only one y-intercept.

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3 years ago

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Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
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3 years ago

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What is 0.75 over 100 simplest form?

STALIN [3.7K]

.0075 is simplest... or .0075/1 if it needs to be a fraction i guess

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3 years ago

Two candidates ran for class president. The candidate that won received 80% of the 290 total votes. How many votes did the winni

s2008m [1.1K]

Answer:

232 total votes

Step-by-step explanation:

change 80% to a decimal.... .8 and then multiply that by 290

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3 years ago

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Use the figure to write the segment addition postulate, write an equation and solve for x.

Alenkinab [10]

Answer:

5. x = -1

6. x = 2

Step-by-step explanation:

5. AB = 5

BC = 2x + 6

AC = x + 10

AB + BC = AC (segment addition postulate)

5 + 2x + 6 = x + 10 (substitution)

Collect like terms

5 + 6 + 2x = x + 10

11 + 2x = x + 10

2x - x = - 11 + 10

x = -1

6. AB = 9x + 7

BC = -3x + 20

AC = 39

AB + BC = AC (segment addition postulate)

(9x + 7) + (-3x + 20) = 39 (substitution)

Solve for x

9x + 7 - 3x + 20 = 39

Collect like terms

9x - 3x + 7 + 20 = 39

6x + 27 = 39

Subtract 27 from both sides

6x + 27 - 27 = 39 - 27

6x = 12

Divided both sides by 6

6x/6 = 12/6

x = 2

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3 years ago