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Varvara68 [4.7K]

2 years ago

5

Need help on both of these please I am really stressed out

2 answers:

Ket [755]2 years ago

6 0

Answer:

sheeeeeeeeeeshshshshshdh

EleoNora [17]2 years ago

4 0

four is d and five is a :) im not sure about the others im sorry

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Y- (z + x - 2); use x = 4, y = 5, and z = 2<br><br> Please evaluate using the values given

frez [133]

It's gonna be 5 - (2 + 4 -2)
according to order of operations, we have to solve inside the parentheses/brackets first (from left to right)

therefore, it will be
5 - (6 - 2)
=5 - (4)

Next, distribute the negative to the four and add normally.

= 5 - 4
= 1

5 0

3 years ago

Read 2 more answers

Whts the solution from this?

Marina CMI [18]

If that’s the right equation... hopefully this helps

6 0

3 years ago

I need<br> 7<br> 50<br> of fuel in %

docker41 [41]

Answer:

14%

Step-by-step explanation:

4 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

3) Find the length of a rectangular lot with a perimeter of 92 m if the length is 8 m more than

Nikolay [14]

Answer:

26 m

Step-by-step explanation:

Perimeter = 92 m

Length = 8 m more than width

Width: 20 m

Therefore,

<h2>length=26 m</h2>

4 0

3 years ago