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2 years ago

153 is 0.9% of what number? Tell which equivalent ratios you used to find the solution.

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

8 0

153 = 0.009n

You did not provide a list of options to select from.

To find n, the ratio leading to the answer is 153/(0.009).

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What is 834% expressed as a fraction?

svetoff [14.1K]

Answer:

8.34/1

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

How do I solve 34-5x+2(x-2)=15

LenKa [72]

34-5x+2(x-2)=15 1st get rid of () by distributing the 2.
34-5x+2x-4=15 Now collect like terms.
30-3x=15 Get -3x by itself by subtracting 30 in both sides.
-3x=-15 You want X by itself so divide by -3 on both sides.
x=5

8 0

2 years ago

olga nikolaevna [1]

Answer:

Fraction of the original board left = $\frac{2}{15}$

Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off $\frac{1}{5}$ of a wooden board.

Length of the board left = l - $(\frac{1}{5})l$

= $(\frac{4}{5})l$ feet

He saws off $\frac{3}{4}th$ of the remaining board,

Board left = $(\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]$

= $\frac{4}{5}l-\frac{3}{5}l$

= $\frac{1}{5}l$ feet

He finally saws off $\frac{1}{3}$ rd of the remaining board.

Board left = $\frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l$

= $(\frac{1}{5}-\frac{1}{15})l$

= $\frac{2}{15}l$ feet

Fraction of the original board left = $\frac{\frac{2}{15}l}{l}$

= $\frac{2}{15}$

6 0

2 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

marishachu [46]

Answer:

$\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

Step-by-step explanation:

We have been given the function

$f(x)=-2x^2+4x^3+3x^2+18$

From the rational zeros theorem, we have

$\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}$

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

$\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

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2 years ago

How does place value help me divide?

Andreyy89

It shows the division ways by doing /

3 0

3 years ago