Question

A deli ordered 6 1/2 wheels of cheese .Over the weekend 3 5/8 wheels of cheese were sold.On Tuesday another wheels were sold.How much cheese was left for Wednesday

Answer 1

Answer:

$1\frac{7}{8}$ wheels of cheese.

Step-by-step explanation:

We have been given that a deli ordered 6 1/2 wheels of cheese. Over the weekend 3 5/8 wheels of cheese were sold. On Tuesday another wheels were sold.

To find the cheese left for Wednesday, we will subtract 3 5/8 and 1 from 6 1/2 as:

$\text{Cheese left for Wednesday}=6\frac{1}{2}-3\frac{5}{8}-1$

Convert mixed fraction into improper fraction:

$\text{Cheese left for Wednesday}=\frac{2\times 6+1}{2}-\frac{3\times 8+5}{8}-1$

$\text{Cheese left for Wednesday}=\frac{13}{2}-\frac{29}{8}-1$

Make a common denominator:

$\text{Cheese left for Wednesday}=\frac{13\times 4}{2\times 4}-\frac{29}{8}-\frac{1\times 8}{8}$

$\text{Cheese left for Wednesday}=\frac{52}{8}-\frac{29}{8}-\frac{8}{8}$

Combine numerators:

$\text{Cheese left for Wednesday}=\frac{52-29-8}{8}$

$\text{Cheese left for Wednesday}=\frac{15}{8}$

$\text{Cheese left for Wednesday}=1\frac{7}{8}$

Therefore, $1\frac{7}{8}$ wheels of cheese was left for Wednesday.