Question

A Hall probe serves to measure magnetic field strength. Such a probe consists of a poor conductor 0.103 mm thick, whose charge-carrier density is 1.11 × 1025 m–3. When a 2.89-A current flows through the probe, the Hall voltage is measured to be 3.47 mV. What is the magnetic field strength?

Answer 1

Answer:

magnetic field strength is 0.315852 T

Explanation:

Given data

thick = 0.103 mm = 0.103 × 10^-3 m

charge-carrier density = 1.11 × 10^25 m^–3

hall voltage = 3.47 mV = 4.99 × 10^-3 V

current = 2.89 A

to find out

magnetic field strength

solution

we will apply here magnetic field strength formula i.e

magnetic field strength = hall voltage × charge-carrier density × magnitude of charge electron ×  thick  / current

here put all these value and magnitude of charge electron is 1.6×10^-19 C

magnetic field strength = hall voltage × charge-carrier density × magnitude of charge electron ×  thick  / current

magnetic field strength = 4.99 × 10^-3 ×  1.11 × 10^25 × 1.6×10^-19 × 0.103 × 10^-3  /  2.89

magnetic field strength = 0.912811 / 2.89

magnetic field strength is 0.315852 T