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Jet001 [13]
4 years ago
8

Can someone help please please asap

Physics
1 answer:
Ronch [10]4 years ago
3 0
Waves and wind because wind can blow the rock or sand away and waves can wash is away
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Assuming perfect optics, if the smallest feature you can resolve when observing around 660 nm is of angular size 0.04 arcsec, wh
Dmitriy789 [7]

Answer:

The value is \theta _2 =  0.08 \ arcsec

Explanation:

From the question we are told that

   The first wavelength is  \lambda_1 =  660 \ nm  = 660 *10^{-9 }

   The  first angular size is  \theta_1 =  0.04 \  arcsec

    The second wavelength is  \lambda _2 =  1320 \  nm  =  1320 *10^{-9 } \  m

Generally according to  Rayleigh Criterion we have that

          \theta=  1.22 *  \frac{\lambda }{D}

given every other thing remains constant we have that

         \theta =  k *  \lambda

Here k  represented constant so

         k  =  \frac{\theta }{\lambda}

=>      \frac{\theta_1}{ \lambda_1}  =  \frac{\theta_2}{ \lambda_2}

=>      \frac{\theta_1}{ \theta_2}  =  \frac{\lambda_1}{ \lambda_2}

So

        \frac{ 0.04}{ \theta_2}  =0.5

=>     \theta _2 =  0.08 \ arcsec

3 0
3 years ago
A ball is dropped from a window and takes two seconds to reach the ground .it starts from rest and reaches a final speed of 20m/
Akimi4 [234]
The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .

If an object starts from rest and its speed after 2 seconds is 20 m/s, then its acceleration is 20/2 = 10 m/s^2 .

(Gravity on Earth is only 9.8 m/s^2.)
3 0
3 years ago
A bullet with a mass of 0.3 kg is fired out of a gun with a mass of 4 kg at 600 m/s. What is the recoil velocity on the gun?
slavikrds [6]

Answer:

According to the Conservation of Momentum,

Momentum of the gun = momentum of the bullet

M(gun)×V(gun)=m(bullet)×v(bullet)

4kg × V = 0.3kg × 600m/s²

V = (0.3 × 600)/4 = 45 m/s

The recoil velocity on the gun is <em><u>45 m/s</u></em>

<h3><u>45 m/s</u> is the right answer.</h3>
4 0
3 years ago
15. To use your left hand to determine the direction of the voltage developed in a moving conductor in a stationary magnetic fie
alukav5142 [94]
<span>"forefinger in the direction of the lines of force" 100% correct, I took the test.</span>
8 0
4 years ago
Read 2 more answers
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
sammy [17]

Answer:

Explanation:

Due to changing magnetic field , there will be emf induced in the region . EMF induced will create electric field which will be circular in shape and will be uniform along its circular path

The magnitude of circular electric field can be calculated as follows

We should apply Faraday law of electro magnetic induction

e = - dФ / dt = - ∫ E dl

Here Ф = π r² B

π r² dB / dt = - ∫ E dl

π r² dB / dt = E x 2π r

E = - r / 2 x dB / dt

For a circular electric field having a particular radius , magnitude of field will be constant .

The direction of electric field will be known by lenz's law

In the given case , magnetic field is upwards and it is reducing , therefore electric field induced will be such as to prevent this change of flux.

So electric field will be anticlock-wise . Hence direction of acceleration will also be  anticlock-wise on proton at 1.5 cm from the centre.

3 0
3 years ago
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