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3 years ago

Select all the correct answers.

Physics

2 answers:

slega [8]3 years ago

8 0

According to the law of gravitation given by Newton, higher the altitudes, less the force of gravity experienced.

Answer: Option A.

<u>Explanation: </u>

The law of gravitation given by Newton, said that the gravity force is experienced more when close to the Earth. Therefore, increase in altitude, means that the individual or the object has gone much above the sea floor, and as the distance increases the force decreases. The force of gravitation is “inversely proportional to distance”.

Rama09 [41]3 years ago

6 0

Answer:

as we move higher altitudes force of gravity us decreases

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Shalnov [3]

Answer:

Explanation:

We will use the KE equation you wrote here and fill in what we are given:

$36=\frac{1}{2}m(12)^2$ and isolating the m:

$m=\frac{2(36)}{12^2}$ which gives us

m = .50 kg

3 0

3 years ago

Two physics students shoot a water-bottle rocket from a 1 m tall stand. They calculate that rocket will travel with the given fo

Kitty [74]

Answer:

2 secs; 65 feet

Explanation:

The function guiding the water bottle is given as:

f(x) = -16t² + 64t + 1

The bottle will reach maximum height when velocity, df/dt (velocity is the first derivative of distance) = 0.

Therefore:

df/dt = 0 = -32t + 64

=> 32t = 64

t = 64/32 = 2 seconds

This is the time it will take to reach the maximum height.

To find this height, we insert t = 2 into the function f(x):

f = -16(2)² + 64(2) + 1

f = -(16 * 4) + 128 + 1

f = -64 + 128 + 1

f = 65 ft

Its maximum height is 65 ft.

7 0

3 years ago

Read 2 more answers

A ship is towed through a narrow channel by applying forces to three ropes attached to its bow. Determine the magnitude and orie

Y_Kistochka [10]

This question is solved using an available similar problem as data provided for the forces was not given.

Repeat the same steps outlined for your problem.

Regards.

Answer:

F = 1.598 KN , Q = 90 degree (+ y-axis)

Explanation:

Sum of Forces in x-direction to the left (+)

2 cos (30) + 3cos (60) + F*cos (Q) = F_a ..... 1

Sum of Forces in y-direction to the up (+)

2 sin (30) + F*sin (Q) - 3 sin (60) ...... 2

Using Eq 2 and solve:

F*sin (Q) = 1.598 KN

F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.

Hence,

F_min = 1.598 KN

Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:

F_a = 2 cos (30) + 3cos (60) = 3.2 KN

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3 years ago

A car drives over a hilltop that has a radius of curvature 0.120 km at the top of the hill. At what speed would the car be trave

Mashutka [201]

Answer:

34.3 m/s

Explanation:

Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration $a_c$ (because the car is moving of circular motion). So at the top of the hill the equation of the forces is:

$mg-R = m a_c = m\frac{v^2}{r}$

where

(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity

R is the normal reaction exerted by the road on the car (upward, so with negative sign)

v is the speed of the car

r = 0.120 km = 120 m is the radius of the curve

The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:

$v=\sqrt{gr}=\sqrt{(9.8 m/s^2)(120 m)}=34.3 m/s$