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Olin [163]
3 years ago
13

How does the electrostatic force compare with the strong nuclear force in the

Physics
2 answers:
soldier1979 [14.2K]3 years ago
7 0

Answer:

The electrostatic force is weaker and acts over longe distances, is the correct answer for Appex/

Explanation:

diamong [38]3 years ago
3 0

Answer:

Strong nuclear force is 1-2 order of magnitude larger than the electrostatic force

Explanation:

There are mainly two forces acting between protons and neutrons in the nucleus:

- The electrostatic force, which is the force exerted between charged particles (therefore, it is exerted between protons only, since neutrons are not charged). The magnitude of the force is given by

F_E=\frac{kq_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 are the  charges of the two particles, r is the separation between the particles.

The force is attractive for two opposite charges and repulsive for two same charges: therefore, the electrostatic force between two protons is repulsive.

- The strong nuclear force, which is the force exerted between nucleons. At short distance (such as in the nucleus), it is attractive, therefore neutrons and protons attract each other and this contributes in keeping the whole nucleus together.

At the scale involved in the nucleus, the strong nuclear force (attractive) is 1-2 order of magnitude larger than the electrostatic force (repulsive), therefore the nucleus stays together and does not break apart.

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Can someone pleaseeee help if you’re correct I’ll give u brainlist
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Answer:

Explanation:

The corona virus Vaccine will have some side effects like soreness in injection area but this will only last for a couple of days. I believe the answer is that there is no long term affect.

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3 years ago
PLEAASE HELP KE WITH THESE THREE YOULL GET POINTS
lozanna [386]

Answer:

  1. 0.0121
  2. 19.8387
  3. 2.2632

Explanation:

1.

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{0.01223}{1.01}\:\\\mathrm{is}\:0.0121

2.

\frac{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&\space\space&4&9&10\\ \space\space&\textbf{1}&9&.&8&\linethrough{5}&\linethrough{10}&\linethrough{0}\\ -&\textbf{0}&0&.&0&1&1&3\end{matrix}}{\begin{matrix}\space\space&\textbf{1}&9&.&8&3&8&7\end{matrix}}\\\\=19.8387

3.

0.1886\times 12\\\\Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer\\1886\times\:12=22632\\\\0.1886\mathrm{\:has\:}4\mathrm{\:decimal\:places}\\12\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}4\mathrm{\:decimal\:places}\\\\=2.2632

3 0
3 years ago
Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm,
REY [17]

Answer:

a) 238U, 40K and 87Rb, b)   235U and to a lesser extent 40K , c)  he 235U,

d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful

Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

Let's write the half-life times of the given materials

87Rb T ½ = 4.75 1010 years

147Sm T ½ = 1.06 1011 years

235U = 7,038 108 years

238U = 4.47 109 years

40K = 1,248 109 years

14C = 5,568 103 years

we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed

c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent

d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed

e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed

f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed

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During the first 5 seconds after a ball is dropped from rest, how far will it fall?
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