Sorry, It seems like i dont have a sign to look of of, I can help you when you post that though!
Answer:
(f + g)(x) = I2x + 1I + 1 ⇒ C
Step-by-step explanation:
Let us solve the question
∵ f(x) = I2x + 1I + 3
∵ g(x) = -2
→ We need to find (f + g)(x), which means add the two functions
∵ (f + g)(x) = f(x) + g(x)
→ Substitute the right side of each function on the right side
∴ (f + g)(x) = I2x + 1I + 3 + (-2)
→ Remember (+)(-) = (-)
∴ (f + g)(x) = I2x + 1I + 3 - 2
→ Add the like terms in the right side
∵ (f + g)(x) = I2x + 1I + (3 - 2)
∴ (f + g)(x) = I2x + 1I + 1
Answer:
1/8=0.125
Step-by-step explanation:
0.125/8 I 1.000 -8 / 20 -16/ 40 -40/0
The last option all the way to the right
