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nasty-shy [4]
3 years ago
8

Two cars start traveling in the same direction around a circular road that is 80 km long. The speed of one car is 92 km/h and th

e sped of the other is 68 km/h. b How many minutes after the two cars start traveling will one car lap the other for the second time?
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

<em><u>No one knows the answer to the mystery...</u></em>

balu736 [363]3 years ago
7 0

Answer:

200 minutes

Step-by-step explanation:

So we know that the speed is 92 km/h for the first car and 68 km/h for the second car. We do not know the time, but we do know that we need to convert it into minutes. The time for both cars would be x/60. Now we multiply speed by time and get distance. The first car would be 92 x/60 and the second would be 68 x/60, now we cross multiply and make an equation. 92x/60 - 68x/60 = 80, 24x = 80, x=200 minutes.

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Identify the values that should be written to complete the X diagram.
cestrela7 [59]

Answer:

See the attachment for what goes on your X diagram.

Rewrite: x² -7x +4x -28

Grouping: (x² -7x) +(4x -28) = x(x -7) +4(x -7) = (x +4)(x -7)

Step-by-step explanation:

The given quadratic is ...

... x² -3x -28 . . . . . a=1, b=-3, c=-28

a) The value at the top of the X diagram is the product a·c = 1·(-28) = -28.

The value at the bottom of the X diagram is the coefficient b = -3.

The values on the sides of the diagram are the factors of -28 that add up to make -3. These are -7 and 4. That is, ...

(-7)·(4) = -28

(-7)+(4) = -3

b) Since the two values on the sides of the diagram add up to give "b", the value of "b" in the equation can be rewritten as the sum of these two numbers. Doing that, we have ...

... x² -3x -28

... = x² +(-7+4)x -28

... = x² -7x +4x -28 . . . . . . order does not matter. It could also be x² +4x -7x -28

c) We can group pairs of terms in the rewritten expression and factor each pair.

... = (x² -7x) +(4x -28) . . . . . first pair has a common factor of x; second pair, 4

... = x(x -7) +4(x -7) . . . . . . . these terms now have a common factor: (x -7)

... = (x +4)(x -7) . . . . . . . . . . the complete factorization of x² -3x -28

3 0
3 years ago
150 thousand times 7
Arada [10]
The equation 150 thousand times 7 equals 1,050,000.

150,000*7= 1050000
8 0
3 years ago
5*213 is a 5 digit number replace the * number by smallest digit to make them divisible by 3​
Elina [12.6K]

Answer:

1

Step-by-step explanation:

that is the answer

because 51213÷3=17071

7 0
3 years ago
Read 2 more answers
Describe a situation you’re familiar with where one quantity changes constantly in relation to another
Crank

Answer:

One such situation is the amount of money in excess you paid for an item and the amount of change you will get. Another such scenario would be the total numbers of hours with respect to the total number of days. With more days, there will be more time hence more hours.

Step-by-step explanation:

8 0
3 years ago
At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

\frac{30}{100}=\frac{1380}{y}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

y=4600.

There are 4600 students who attend the university.

7 0
3 years ago
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