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nasty-shy [4]
3 years ago
8

Two cars start traveling in the same direction around a circular road that is 80 km long. The speed of one car is 92 km/h and th

e sped of the other is 68 km/h. b How many minutes after the two cars start traveling will one car lap the other for the second time?
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

<em><u>No one knows the answer to the mystery...</u></em>

balu736 [363]3 years ago
7 0

Answer:

200 minutes

Step-by-step explanation:

So we know that the speed is 92 km/h for the first car and 68 km/h for the second car. We do not know the time, but we do know that we need to convert it into minutes. The time for both cars would be x/60. Now we multiply speed by time and get distance. The first car would be 92 x/60 and the second would be 68 x/60, now we cross multiply and make an equation. 92x/60 - 68x/60 = 80, 24x = 80, x=200 minutes.

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stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
Write an inequality to represent the possible<br> combinations of x cupcakes and y cakes sold.
kolezko [41]

Answer:

The inequality for this would be n ≥ 20.

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Step-by-step explanation:

6 0
2 years ago
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SOVA2 [1]

Answer:

a = -2

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Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

or

a = 4b - 6 .............(2)

2b + c = 7

or

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substituting 2 and 3 in  1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

or

8b - 12 + 4b + 7 - 2b = 5

or

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or

b = 1

substituting b in 2, we get

a = 4(1) - 6

or

a = -2

substituting b in 3, we get

c = 7 - 2(1)

or

c = 5

thus,

a = -2

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2 years ago
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Galina-37 [17]

Answer:

2

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7 0
2 years ago
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Answer:

x=63

Step-by-step explanation:

55+62+x=180

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