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nasty-shy [4]
3 years ago
8

Two cars start traveling in the same direction around a circular road that is 80 km long. The speed of one car is 92 km/h and th

e sped of the other is 68 km/h. b How many minutes after the two cars start traveling will one car lap the other for the second time?
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

<em><u>No one knows the answer to the mystery...</u></em>

balu736 [363]3 years ago
7 0

Answer:

200 minutes

Step-by-step explanation:

So we know that the speed is 92 km/h for the first car and 68 km/h for the second car. We do not know the time, but we do know that we need to convert it into minutes. The time for both cars would be x/60. Now we multiply speed by time and get distance. The first car would be 92 x/60 and the second would be 68 x/60, now we cross multiply and make an equation. 92x/60 - 68x/60 = 80, 24x = 80, x=200 minutes.

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6(4x+2)=3(8x+4) ??<br> please help asap
nasty-shy [4]
6(4x + 2) = 3(8x + 4)

Reorder the terms:
6(2 + 4x) = 3(8x + 4)
(2 * 6 + 4x * 6) = 3(8x + 4)
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Reorder the terms:
12 + 24x = 3(4 + 8x)
12 + 24x = (4 * 3 + 8x * 3)
12 + 24x = (12 + 24x)

Add '-12' to each side of the equation.
12 + -12 + 24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
0 + 24x = 12 + -12 + 24x
24x = 12 + -12 + 24x

Combine like terms: 12 + -12 = 0
24x = 0 + 24x
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Add '-24x' to each side of the equation.
24x + -24x = 24x + -24x

Combine like terms: 24x + -24x = 0
0 = 24x + -24x

Combine like terms: 24x + -24x = 0
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Solving
0 = 0
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