All categories

4 years ago

PLS HELP ASAP I WILL GIVE BRANERLIST PLUS 9 POINTS

Mathematics

1 answer:

sweet-ann [11.9K]4 years ago

3 0

Answer:

To find this answer, simply experiment with plugging in values for n and see what values you get, and what makes sense. In this problem, only the first option makes sense, given the expression of $\frac{500}{n}$ .

You might be interested in

−4 x + 10 ≥ 5 x + 55

Andrew [12]

Answer:

Step-by-step explanation:

If I were to solve for x, the answer would be x ≤ − 5.

6 0

3 years ago

Read 2 more answers

James buys a shirt and a pair of socks on sale for 25% off. If the price of the shirt before the sale was $24 and he spent a tot

lesantik [10]

Answer:

The price of the socks is dollar 8

Pls mark nrainliest

4 0

4 years ago

Read 2 more answers

| 18 - (-13) | it’s subtracting integers

Anna35 [415]

Answer: 31

How: If there are two negative signs like this, you would connect them together and make it into a addition sign where you then can add them.

7 0

3 years ago

PLEASE HURRY I'M BEING TIMED

kobusy [5.1K]

Answer:

i think the answer is D my guy

Step-by-step explanation:

do you need the steps??

mark brainliest :p

6 0

3 years ago

A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco

IceJOKER [234]

Events

• A: an even number is rolled in the first time

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

$\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}$

The probability of rolling a number greater than 3 is:

$\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}$

Events A and B are independent, then the probability of one happening after the other is:

$\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}$

8 0

1 year ago