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kherson [118]
2 years ago
10

Please can help me with this problem ? Thanks

Mathematics
1 answer:
larisa86 [58]2 years ago
7 0
Order the numbers by magnitude (size) and watch the negative signs:

-12, -1, 0, 2, 15, 18

Answer: C 
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Anni [7]

i think the question is not correct write it again or attach the pic ic

6 0
2 years ago
What is larger 8/10 or 63/100
amid [387]

Answer:

8/10

Step-by-step explanation:

8/10 = 80/100 > 63/100

6 0
3 years ago
Read 2 more answers
A rabbit traveled 60 meters in 4 seconds. what is the unit rate? enter your answer into the box.
blondinia [14]
60 meters
4 seconds

To find the unit rate, divide the distance by the time.

60/4=15meters per second= 15m/s
4 0
2 years ago
Help please and thank you!
Usimov [2.4K]

Answer:

Option A

Explanation:

\rightarrow \sf sin\left(\dfrac{7\pi }{6}\right)

\rightarrow \sf \sin \left(\pi +\dfrac{\pi }{6}\right)

\rightarrow \sin \left(\pi \right)\cos \left(\dfrac{\pi }{6}\right)+\cos \left(\pi \right)\sin \left(\dfrac{\pi }{6}\right)

\rightarrow \sf 0 *  \dfrac{\sqrt{3}}{2}+\left(-1\right) * \dfrac{1}{2}

\rightarrow \sf -\dfrac{1}{2}

7 0
2 years ago
(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
slavikrds [6]

Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
3 years ago
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