Answer:
15th term = 116
Step-by-step explanation:
a= 4
Sum of an A.P = n/2 {2a + (n-1)d}
sum of first five term is equal to one-fourth of the sum of the next five term
5/2{ 2*4 + (5-1)d} = 1/4 × 10/2{2*4 + (10-1)d
5/2 {8 + 4d} = 1/4 × 5{ 8 + 9d}
40/2 + 20/2d = 1/4{ 40 + 45d)
20 + 10d= 40/4 + 45/4d
20 + 10d = 10 + 45/4d
20 - 10 = 45/4d - 10d
10 =45d - 40d /4
10 = 5/4d
Divide both sides by 5/4
10 ÷5/4 = d
10×4/5 = d
40/5 = d
8 = d
d= 8
Find the 15th term
15th term = a + (n-1)d
= 4 + (15-1)8
= 4 + (14)8
= 4 + 112
= 116
The 15th term is 116
Trig!!!-
We can use trig function to find the answer-
we know that tangent is opp/adjacent
Thus c=180-32-25=123 degrees and
tan 123=18/c
This c=34.7539008597 since it is tan 123=0.51792747158 and we use algebra to solve for c and it is 18/tan 123=c and then c=34.8 when we round to the nearest tenth
Vote my answer for the brainiest pls
Answer:
9
Step-by-step explanation:
x = first number
3x = second number
2x = third number
27 = x + 3x+ 2x
27 = 6x
x=4.5 (first number)
3(4.5) = 13.5 (second number)
2(4.5) = 9 (third number)
(4.5 + 13.5 + 9) /3 = 9
Wow after doing all that I realized that all you had to do was 27/3 since there's 3 numbers.
