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storchak [24]
2 years ago
12

Find f(-5) if f( x ) = | x + 1|.

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
8 0

Answer:

Step-by-step explanation:

f(x)=x+1

then,

   f(-5)=(-5)+1

         =-4

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Give an approximation of underroot(3) correct to hundredths. (Round to two decimal places as needed.)
Igoryamba

Answer: 1.75

Step-by-step explanation:

To find the value of \sqrt{3}

\text{Let , }y=\sqrt{x}

\text{And Let x = 4 and }\Delta x=-1

Now,

\Delta y=\sqrt{x+\Delta x}-\sqrt{x}\\\\=\sqrt{3}-\sqrt{4}=\sqrt{3}-2\\\\\Rightarrow\ \sqrt{3}=\Delta y+2

Since dy is approximately equals to \Delta y then ,

dy=\dfrac{dy}{dx}\Delta x\\\\=\dfrac{1}{2\sqrt{x}}\times(-1)=\dfrac{1}{2\sqrt{4}}\times(-1)=-0.25

Thus , the approximate value of  \sqrt{3}=-0.25+2=1.75

8 0
4 years ago
Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

7 0
3 years ago
The distance traveled by a toy car can be modeled by D(t) = t3 − 3t2 + t − 3, where t &gt; 3 represents time in seconds. If the
Bogdan [553]

Answer:

t^2+1

Step-by-step explanation:

We are given that

Distance traveled by a toy car

D(t)=t^3-3t^2+t-3

Where t>3

Time taken by car =t-3 seconds

We have to find the expression which represents the speed of the toy car.

We know that

Speed=\frac{Distance}{time}

Using the formula

Speed=\frac{(t^3-3t^2+t-3)}{t-3}

Speed=\frac{t^2(t-3)+(t-3)}{t-3}

Speed=\frac{(t-3)(t^2+1)}{t-3}

Speed=t^2+1

Hence, the expression  which represents the speed of the toy car

t^2+1

5 0
3 years ago
Each of 8 samples has a different standard deviation . How many of the 8 samples could be from the same population ?
Lynna [10]
The answer is c you are welcome
5 0
3 years ago
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Two cards are chosen at random without replacement what is the probability of getting two aces
VARVARA [1.3K]
4/52 chance of getting an ace.
4 0
4 years ago
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