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LekaFEV [45]
3 years ago
9

Find the slope between the two pairs (3,7) (2,9)​

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0
The answer to this would be 1/3
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Total employment for sheet metal workers in 2016 is projected to be 201,000. If this is a 6.3% increase from 2006,
anastassius [24]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
150 decreased by 60%
kodGreya [7K]
Hello there the answer to your question would be 60. Since 150-(60%*150) = 150 - 60 *150 = (1-60%)*150 = (100%-60%) * 150= 40% * 150 = 40/100 * 150 = 40 * 150 ÷ 100 = 6000/100 = 60. Hope this helps you out, have a great day!
8 0
3 years ago
The vertices of a triangle are P(−3, −4), Q(3, 4), and R(−6, −3). Name the vertices of Rx = 0 (PQR).
Katyanochek1 [597]
The correct answer is <span>A) P'(3, −4), Q'(−3, 4), R'(6, −3)</span>

Rx = 0 indicates a reflection over the y-axis. 

The rule for such a transformation is:
(x, y) --> (-x, y)
which means that the x-coordinate changes sign and the y-coordinate stays the same.

Therefore:
P<span>(-3, -4) --> P'(3, -4)
Q(3, 4) --> Q'(-3, 4)
R(-6, -3)</span> --> R'(6, -3)

These points are those in option A).
6 0
3 years ago
If an object is moving at a changing speed in the same direction what is the acceleration of the object (zero or not Zero)
andreyandreev [35.5K]

Answer:

zero

Step-by-step explanation:

hope its help thank you sa points

8 0
2 years ago
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Find a formula for the distance from the point​ P(x,y,z) to each of the following planes. a. Find the distance from​ P(x,y,z) to
BARSIC [14]

Answer:

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

Step-by-step explanation:

The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z

Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

7 0
3 years ago
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