Answer:
<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>
Step-by-step explanation:
<h3>#CarryOnLearning</h3>
Hello there the answer to your question would be 60. Since 150-(60%*150) = 150 - 60 *150 = (1-60%)*150 = (100%-60%) * 150= 40% * 150 = 40/100 * 150 = 40 * 150 ÷ 100 = 6000/100 = 60. Hope this helps you out, have a great day!
The correct answer is <span>A) P'(3, −4), Q'(−3, 4), R'(6, −3)</span>
Rx = 0 indicates a reflection over the y-axis.
The rule for such a transformation is:
(x, y) --> (-x, y)
which means that the x-coordinate changes sign and the y-coordinate stays the same.
Therefore:
P<span>(-3, -4) --> P'(3, -4)
Q(3, 4) --> Q'(-3, 4)
R(-6, -3)</span> --> R'(6, -3)
These points are those in option A).
Answer:
zero
Step-by-step explanation:
hope its help thank you sa points
Answer:
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Step-by-step explanation:
The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z
Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
