Answer:
11:40am because 50 mins before 12:30pm is 11:40am
Answer:
A is the answer
Step-by-step explanation:
Answer:alright so what’s your questions?
Step-by-step explanation:what’s the question
<span>We have the following polynomial:
![f(x)=2x^{3}+9x^{2}+7x-6](https://tex.z-dn.net/?f=f%28x%29%3D2x%5E%7B3%7D%2B9x%5E%7B2%7D%2B7x-6)
The problem states that one root is -3. Thus, it is true that
![(x+3)](https://tex.z-dn.net/?f=%28x%2B3%29)
is a factor of the polynomial. Given that this is fulfilled, it is also true that:
</span>
![f(x)=(x+3)Q(x) \therefore Q(x)=\frac{f(x)}{x+3} \\ \\ where \ Q(x) \ has \ a \ degree \ of \ 2](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B3%29Q%28x%29%20%5Ctherefore%20Q%28x%29%3D%5Cfrac%7Bf%28x%29%7D%7Bx%2B3%7D%20%5C%5C%20%5C%5C%20where%20%5C%20Q%28x%29%20%5C%20has%20%5C%20a%20%5C%20degree%20%5C%20of%20%5C%202)
<span>
We can find Q(x) by applying Ruffini's rule, thus:
</span>
![\ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ 7 \ \ \ \ \ \ -6 \\ -3 \\ \rule{50mm}{0.1mm} \\ \ {} \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 3 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ 0](https://tex.z-dn.net/?f=%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%202%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%209%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%207%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20-6%20%20%5C%5C%20-3%20%5C%5C%20%5Crule%7B50mm%7D%7B0.1mm%7D%20%5C%5C%20%5C%20%7B%7D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%202%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%203%20%5C%20%5C%20%5C%20%5C%20%5C%20-2%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%200)
<span>
Therefore:
The roots of this polynomial can be get as follows:
These are the roots along with
![-3](https://tex.z-dn.net/?f=-3)
. Finally, the factored polynomial can be written as follows:
![f(x)=(x+3)(x+2)(2x-1)](https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B3%29%28x%2B2%29%282x-1%29)
</span>