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3 years ago

Select the expressions that are equivalent to 18m - 12.

Mathematics

1 answer:

krok68 [10]3 years ago

4 0

Answer:

All the expressions other than option E, is equivalent to the expression 18m - 12.

Step-by-step explanation:

A. 6m - 4 + 6m -4 + 6m - 4

or 6m+6m+6m -4 -4 -4

or 18m -12

B. 12m + 6 - 6m -6

or 12m - 6m + 6 - 6

or 6m

C.6(3m - 2)

or 18m - 12

D.3(6m - 4)

or 18m - 12

E. 24n - 4² + 8 -6m

This option can not satisfy the given expression as it contains another variable as n.

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This year consumers purchased 7,234,267,990 bottles of water. Last year consumers purchased 2,000,900,999 bottles of water. Whic

torisob [31]

Answer:

B. 9,000,000,000

Step-by-step explanation:

From the given information:

We are to determine the best estimate of the number of bottles sold this year and last year.

The best estimate means rounding up to the nearest whole number.

Given that:

7,234,267,990 bottles of water were purchased this year

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3 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$