Answer:
There are a total of 23 cars with air conditioning and automatic transmission but not power steering
Step-by-step explanation:
Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.
Remember that for 2 sets E and F, we have that

Also,
|E| = |E ∩F| + |E∩F^c|
We now alredy the following:
|A| = 89
|B| = 99
|C| = 74

|(A \cup B \cup C)^c| = 24
|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).
|B \ (AUC)| = 65
|C \ (AUB)| = 26

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things
For example:
99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|
Therefore, |B∩C^c| = 99-11 = 88
And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.
This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.
Hey there!
Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.
Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

Distribute:

Subtract:

Divide:

Your answer is C.
Hope this helps!
Answer:
RS = 5
Step-by-step explanation:
Since R is between Q and S , then
QS = QR + RS , that is
6x - 3 = 3x - 2 + 2x + 1
6x - 3 = 5x - 1 ( subtract 5x from both sides )
x - 3 = - 1 ( add 3 to both sides )
x = 2
Then
RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5
Answer:
43.20 for the total cost of the item
1350 (dont take my word for it, but i belive this is right)