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2 years ago

8

On a Saturday, Saul can cut 4 lawns in 6 hours. If Mitch can mow lawns at the same rate, how long will it take him to mow 9 lawn

s?
12 hours
12 3/4 hours
6 hours
13 1/2 hours

1 answer:

alukav5142 [94]2 years ago

6 0

Answer:

13 1/2 this is the answer

:)

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Vaselesa [24]

It can work well here to simplify inside parentheses first.

$\displaystyle\left(\frac{4x^{-2}y^{2}}{12x^{-4}y^{-1}}\right)^{3}=\left(\frac{4}{12}x^{(-2-(-4))}y^{(2-(-1))}\right)^{3}\\\\=\left(\frac{x^{2}y^{3}}{3}\right)^{3}=\frac{x^{(2\cdot 3)}y^{(3\cdot 3)}}{3^{3}}\\\\=\frac{x^{6}y^{9}}{27}$

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3 years ago

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8. 6r + 5 = 4 6 - 7y -20

Rudiy27

Answer: r=-7/6y+7/2

Step-by-step explanation:

Step 1: Add -5 to both sides.

6r+5+−5=−7y+26+−5

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Step 2: Divide both sides by 6.

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2 years ago

300 cubic inches to cubic centimeters?

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Independent Practice

aleksklad [387]

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A.

2 72 square root of 7

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3 years ago

Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest

Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440 – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

$\text {Simple Interest }=\frac{P \times R \times T}{100}$

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

$1840=\frac{4600 \times R \times 5}{100}$

$\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}$

Hence, the required rate of interest per year is 8%

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3 years ago