Answer:
Step-by-step explanation:
Given that X no of students applying for Honors college is binomial with n =1500 and p = 0.13
a) Mean = E(x) = np = ![1500(0.13)\\= 195](https://tex.z-dn.net/?f=1500%280.13%29%5C%5C%3D%20195)
b) Variance= npq =![195(0.87)\\= 169.65](https://tex.z-dn.net/?f=195%280.87%29%5C%5C%3D%20169.65)
Std dev =13.025
c) Var = 169.65
d) P(X<160)
=0.00261
e) P(X>200) = 1-F(200)=0.3336
![P(X=r) = 1500Cr (0.13)^r (0.87)^{155-r}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%201500Cr%20%280.13%29%5Er%20%280.87%29%5E%7B155-r%7D)
is the formula used.
Answer:
The total number of the payments is 18 ⇒ answer A
Step-by-step explanation:
* Lets revise the rule of compounded monthly payment
→
, where
- A is the loan amount
- r is monthly interest in decimal (R/12*100))
- n the total number of payments
∵ A = $1100
∵ EMI = $71.5
- Interest rate is 19.2% APR
∵ r = ![\frac{19.2}{12*100}=0.016](https://tex.z-dn.net/?f=%5Cfrac%7B19.2%7D%7B12%2A100%7D%3D0.016)
- Substitute these values in the rule to find n
∴ 71.5 = ![\frac{1100(0.016)}{[1-\frac{1}{(1+0.016)^{n}}]}=\frac{17.6}{[1-\frac{1}{(1.016)^{n}}]}](https://tex.z-dn.net/?f=%5Cfrac%7B1100%280.016%29%7D%7B%5B1-%5Cfrac%7B1%7D%7B%281%2B0.016%29%5E%7Bn%7D%7D%5D%7D%3D%5Cfrac%7B17.6%7D%7B%5B1-%5Cfrac%7B1%7D%7B%281.016%29%5E%7Bn%7D%7D%5D%7D)
- By using cross multiplication
∴ 71.5[1 -
] = 17.6
- Divide both sides by 71.5
∴ 1 -
= ![\frac{16}{65}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B65%7D)
- Subtract 1 from both sides
∴ -
= - ![\frac{49}{65}](https://tex.z-dn.net/?f=%5Cfrac%7B49%7D%7B65%7D)
- Multiply both sides by -1
∴
= ![\frac{49}{65}](https://tex.z-dn.net/?f=%5Cfrac%7B49%7D%7B65%7D)
- By using cross multiplication
∴ 49[
] = 65
- Divide both sides by 49
∴
= ![\frac{65}{49}](https://tex.z-dn.net/?f=%5Cfrac%7B65%7D%7B49%7D)
- Insert log for both sides
∴ ㏒
= log(
)
- Put n in-front of the ㏒
∴ n㏒(1.016) = ㏒(
)
- Divide both sides by ㏒(1.016)
∴ n = 17.8 ≅ 18
* <em>The total number of the payments is 18</em>
Answer:
a. (x+19)(x+1)
b. (z-1)(z-1)
c. 3(2x-3)
Step-by-step explanation:
a. x^2+20x+19
(x+19)(x+1)
b. z^2-2z+1
(z-1)(z-1)
c. 9(x-1)-3x
9x-9-3x
6x-9
3(2x-3)
A. 10/15
b. 7/8
those r the answers