Question

Henrique drew and labeled the net shown. He also labeled the areas of the left and right triangular sides.

Answer 1

Answer:

117.2

Step-by-step explanation:

Answer 2

Answer: $SA=117.2\ in^2$

Step-by-step explanation:

You need to remember the following:

1. The area of a rectangle can be calculated with the following formula:

$A_r=lw$

Where "l" is the length and "w" is the width.

2. The area of a triangle can be calculated with the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

Use those formulas to find the area of each face.

Area of the rectangle

$A_r=(10\ in)(4\ in)=40\ in^2$

Area of two triangles

There are two equal triangles. Each one has a base  of 10 inches and a height of 5 inches. Then, their areas are equal:

$A_{t1}=A_{t2}=\frac{(10\ in)(5\ in)}{2}=25\ in^2$

The areas of the other two triangles (which are equal) are:

$A_{t3}=A_{t4}=13.6\ in^2$

Adding the areas of the faces, you get that the surface area of the rectangular pyramid is:

$SA=40\ in^2+25\ in^2+25\ in^2+13.6\ in^2+13.6\ in^2\\\\SA=117.2\ in^2$