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Sergio039 [100]
2 years ago
15

mr. Brown teaches fourth grade at the Carly Adams school he has a class with 40 total students in it and 17 of those students ar

e girls what is the ratio of girls to Boys in Mr Brown's class​
Mathematics
1 answer:
nikitadnepr [17]2 years ago
3 0

Answer:

girls:boys would be 17:23

Step-by-step explanation:

first you would take the amount of students which is 40 and subtract the amount of girls which is 17 and you would get 23 which would be the amount of boys, so he ratio would be 17:23

Hope this helps !

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3 years ago
Algebra 1 Assignment! Help needed as soon as possible! thanks so much to whoever helps! have a nice day
mezya [45]

Answer:

Step-by-step explanation:

go-kart = Gk

Head sock = Hs   (what?  a sock in the head?  :/ what ?? )

Laser tag = Lt

Eq 1 ) Gk + Hs + Lt = 33

Eq 2) 2Gk + Hs + 0Lt = 48

Eq 3) 2Gk + Hs + 2Lt =64

This is a system of equations  w/ 3 unknowns and 3 equations so we can solve this. :)

subtract Eq 2 from Eq 3

  2Gk +Hs +2Lt =64

-(2Gk +Hs +0Lt =48)

0Gk + 0 Hs +2Lt = 16

Lt =8    

so one Laser tag game is 8 dollars.. good... now use  8 in Eq. 1 and 3 for Lt price

Eq 1a) Gk + Hs +8 =33    simplify

Eq 1b) Gk + Hs = 25

Eq 3a) 2Gk +Hs +2(8) = 64  simplify

Eq3b) 2Gk + Hs =48

subtract Eq 1b from Eq 3b

2Gk + Hs =48

-(Gk + Hs =25)

Gk = 23

so one Gk ride costs 23 dollars and plug this into Eq 1

23 + Hs + 8 = 33

Hs = 2

Question 1  )  Gk = 23  Hs = 2 Lt = 8

solve new systems, same as above but  with the new prices

Eq 1r ) Gk + Hs + Lt = 18

Eq 2r) 2Gk + Hs + 0Lt = 29

Eq 3r) 2Gk + Hs + 2Lt =35

subtracting 2r from 3r we get 2Lt = 6   then Lt =3  for the new price

plug that into 1r and 3r

Eq 1br) Gk + Hs = 15

Eq 3br) 2Gk +Hs = 29

subtract 1br from 3br

 Gk = 14

plug this into 1r

Hs =1

Question 2 ) Gk=14 Hs =1 Lt=3

Question 3)  wants 2 Hs and 2 Lt

w/o coupon the activities cost 2 ( 2+8)  = 20 dollars

but there is no coupon for 2 of each game

so  no, don't buy a coupon.. just play at full price

Hustler side note.. buy two of the 18 coupons and sell the 2 Gk rides to your   teacher for 15 dollars each, still a good deal to guarantee a good grade on your Home Work ..  (30 total)...... and get your games for just 6 dollars... excellent deal for you   :)

8 0
2 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
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