Answer:
6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy
Step-by-step explanation:
Here, we want to produce 36 kg of 25% alloy
Let the Pure copper be x kg while 10% alloy be y kg
Pure copper is simply 100% copper
Thus;
x + y = 36 •••••(i)
Then;
100% of x + 10% of y = 25% of 36
= x + 0.1y = 9 •••••• ii)
From i x = 36-y
from ii, x = 9-0.1y
Equate both x
36-y = 9-0.1y
36-9 = 0.1y + y
0.9y = 27
y = 27/0.9
y = 30
x = 36-y
x = 36-30
x = 6 kg
To solve this inequality, you need to isolate the value of u. To do this, divide both sides by -2. When you do this, keep in mind that when you divide or multiply both sides by a negative in an inequality, you MUST flip the sign, so your answer would be -8 < u or u > -8.
Answer:
-8
Step-by-step explanation:
Answer:
See method below.
Step-by-step explanation:
m/n + n/3 = 2
2/m + n = 4
First eliminate the fractions by multiplying the first equation by 3n:-
3m + n^2 = 6n...........(1)
and the second equation by m:-
2 + mn = 4m..............(2)
Now we solve using substitution:-
From equation (2):-
4m - mn = 2
m = 2 / (4 - n)
Now substitute for m in equation (1):-
6/ (4 - n) + n^2 = 6n
6 + n^2(4 - n) = 6n(4 - n)
6 + 4n^2 - n^3 = 24n - 6n^2
n^3 - 10n^2 + 24n - 6 = 0
This will not factor so we could solve this using graphical software.
To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.
I don't really know how to explain it to you but what I can tell you is that in 1 centigram there are 10 milligrams.
