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3 years ago

13

Solve the inequality 2x + 11 =<5x - 10

2 answers:

Yuri [45]3 years ago

4 0

<span>13 i think srry if i get it wrong</span>

nirvana33 [79]3 years ago

3 0

3 is your answer. I hope I helped!

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Jada was at the state fair from 8:45 am until 11:00 am. How much time did Jada spend at the state fair?

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4. Find all the solutions to each equation.<br> x2=81<br> x2=100<br> x=12

alisha [4.7K]

Answer:

x2=81 x=9 and x=-9

x2=100 x=10 and x=-10

x=12 nothing you can solve for in this equation. X=12

Step-by-step explanation:

x2=81

Divide 81 by 2 and get x by it self

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6 0

3 years ago

Please solve these with the full explained answer

statuscvo [17]

ANSWER TO QUESTION 1

The given equation is

$4x+10=-26$

We add the additive inverse of $10$ which is $-10$ to both sides of the equation to obtain,

$4x+10+-10=-26+-10$

This gives us,

$4x+10-10=-26-10$

$4x+0=-36$

This further simplifies to

$4x=-36$

We divide both sides $4$ to obtain,

$x=-4$

ANSWER TO QUESTION 2

Since we got $-4$ as answer to question one, the next question to answer is

$\frac{x}{3}+10=15$

We add the additive inverse of $10$ which is $-10$ to both sides to obtain,

$\frac{x}{3}+10+-10=15+-10$

This gives us,

$\frac{x}{3}+10-10=15-10$

This simplifies to

$\frac{x}{3}+0=5$

$\frac{x}{3}=5$

We now multiply both sides of the equation by $3$ to obtain,

$3\times \frac{x}{3}=5\times3$

This implies that,

$x=15$

ANSWER TO QUESTION 3

The next equation is $9-2x=35$

We add the additive inverse of $9$ which is $-9$ to both sides of the equation to obtain,

$9+-9-2x=35+-9$

This gives us,

$9-9-2x=35-9$

This simplifies to,

$-2x=26$

We multiply both sides by the reciprocal or the multiplicative inverse of $-2$ to obtain,

$-2x\times (-\frac{1}{2})=26\times(-\frac{1}{2})$

This gives us,

$x=-13$

ANSWER TO QUESTION 4.

The next question is $\frac{2}{3}x+15=17$

We add the additive inverse of 15 to both sides of the equation to obtain,

$\frac{2}{3}x+15+-15=17+-15$

This evaluates to

$\frac{2}{3}x+0=17-15$

This implies that,

$\frac{2}{3}x=2$

We multiply both sides by the multiplicative inverse or the reciprocal of $\frac{2}{3}$

This implies that,

$x=2\times\frac{3}{2}$

$x=3$

ANSWER TO QUESTION 5

The next question to answer is $-5x-10=10$ .

We add the additive inverse of $-10$ which is $10$ to both sides of the equation to obtain,

$-5x-10+10=10+10$

This gives us,

$-5x=20$

We through by $-10$ to obtain,

$x=-4$

ANSWER TO QUESTION 6

$\frac{3}{4}x-9=27$

We add the additive inverse of $-9$ which is $9$ to both sides of the equation to obtain,

$\frac{3}{4}x-9+9=27+9$

This simplifies to;

$\frac{3}{4}x=36$

We multiply both sides of the equation by the reciprocal of $\frac{3}{4}$ to obtain,

$\frac{3}{4}x \times \frac{4}{3}=36\times \frac{4}{3}$

$x=36\times \frac{4}{3}$

$x=12\times 4$

$x=48$

ANSWER TO QUESTION 7

The next question to answer is $\frac{1}{2}x+13=9$ .

We add the additive inverse of $13$ which is $-13$ to both sides of the equation to obtain,

$\frac{1}{2}x+13+-13=9+-13$

This will evaluate to,

$\frac{1}{2}x=-4$

We now multiply both sides of the equation by $2$ to obtain,

$x=-4\times 2$

$x=-8$

ANSWER TO QUESTION 8

The last question to solve now is $\frac{x-7}{4}=-2$

We first of all multiply both sides of the equation by $4$ to obtain,

$\frac{x-7}{4} \times 4=-2\times 4$

This implies that,

$x-7=-8$

We now add the additive inverse of $-7$ which is 7 to both sides of the equation to obtain,

$x-7+7=-8+7$

This implies that

$x=-1$

3 0

4 years ago

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