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4 years ago

What causes the hydro carbons to condense in the fractional distillation process?

Chemistry

1 answer:

Elina [12.6K]4 years ago

8 0

Answer:

Substances with high boiling points condense at the bottom and substances with lower boiling points condense on the way to the top. The crude oil is evaporated and its vapours condense at different temperatures in the fractionating column.

Explanation:

answer above

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What is Delta.Gsystem for the system that is described by the following data? Delta.Hsystem = –345 kJ, T = 293 K, Delta.Ssystem

ryzh [129]

Answer:

-209 kJ

Explanation:

I did the math. You're welcome ;)

6 0

4 years ago

Natural gas is stored in a spherical tank at a temperature of 13°C. At a given initial time, the pressure in the tank is 117 kPa

drek231 [11]

Answer:

1. the absolute pressure in the tank before filling = 217 kPa

2. the absolute pressure in the tank after filling = 312 kPa

3. the ratio of the mass after filling M2 to that before filling M1 = 1.44

The correct relation is option c ( $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$ )

Explanation:

To find -

1. What is the absolute pressure in the tank before filling?

2. What is the absolute pressure in the tank after filling?

3. What is the ratio of the mass after filling M2 to that before filling M1 for this situation?

As we know that ,

Absolute pressure = Atmospheric pressure + Gage pressure

So,

Before filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 117 kPa

⇒Absolute pressure ( p1 ) = 100 + 117 = 217 kPa

Now,

After filling the tank :

Given - Atmospheric pressure = 100 kPa , Gage pressure = 212 kPa

⇒Absolute pressure (p2) = 100 + 212= 312 kPa

Now,

As given, volume is the same before and after filling,

i.e. $V_{1}$ = $V_{2}$

As we know that, P ∝ M

⇒ $\frac{p_{1} }{p_{2} } = \frac{m_{1} }{m_{2} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{p_{2} }{p_{1} }$

⇒ $\frac{m_{2} }{m_{1} } = \frac{312 }{217 } = 1.4378$ ≈ 1.44

Now, as we know that PV = nRT

As V is constant

⇒ P ∝ MT

⇒ $\frac{P}{T}$ ∝ M

⇒ $\frac{M_{2} }{M_{1} } = \frac{P_{2} T_{1} }{P_{1} T_{2} }$

So, The correct relation is c option.

6 0

3 years ago

What is the volume of the rock in the image in mL

Yuri [45]

Answer:

Initial volume: mL

Final volume: mL

Volume of rock: cm3

5 0

3 years ago

How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)

11Alexandr11 [23.1K]

$98.56 dm^3$ of oxygen at STP would be required to react completely with 38.8g of propane.

Given that :

molar mass of propane = 44 g/mol

mass of propane = 38.8 g

∴ Moles present in 38.8 g of propane = $\frac{38.8}{44}$ = 0.88 mole

applying rule of balanced equations

1 mole of propane = 5 moles of oxygen

0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen

Note : volume of 1 mole of oxygen at STP = $22.4 dm^3$

∴Total volume of oxygen required at STP = 22.4 * 4.4 = $98.56 dm^3$

Hence we can conclude that the volume of oxygen at STP required to react completely $98.56 dm^3$

Learn more : brainly.com/question/16998374

5 0

2 years ago

Look at the graph. Which part of the line shows a time when the object was not moving?

marysya [2.9K]

Answer:

$\bold \blue{b)B}$

hope it helps :)

7 0

2 years ago

Read 2 more answers