4 years ago

Solve the linear equation.

Mathematics

2 answers:

kondor19780726 [428]4 years ago

4 0

Answer:

B. No Solutions

True [87]4 years ago

3 0

Answer:

no solution

Step-by-step explanation:

because if you add the x's you get 8x and then when you subtract the 8x to both side they cancel so you get 1=-5 so that makes a no solution

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Find all zeros of x^4+x

Yuri [45]

Answer:

-1 and 0

Step-by-step explanation:

X ^4+x = 0;

x*(x^3+1)=0;

x*[(x^3-x)+(x+1)]=0;

x*[x(x-1)(x+1)+(x+1)]=0;

x*(x+1)(x^2-x+1)=0;

Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0

x=0 or -1

4 0

2 years ago

Please help me:////.

Hitman42 [59]

The absolute value of a number is its distance from 0. An easy way to think about this is that the absolute value turns a negative number positive, and has no effect on positive numbers. In this case, we are taking the absolute value of a negative number. This means we should simply make the number positive. Therefore, the answer is $\frac{1}{3}$