Answer:
200X = Y
Step-by-step explanation:
Since the insect in question can flap its wings 200 times per second, the equation that represents how many times it flaps its wings according to the time of flight is the following:
200X = Y
Thus, 200 is the number of times per second it flaps its wings, while X is the number of seconds in question. In turn, Y is the number of times it flaps its wings in the given time.
For example, if the insect were to fly for 5 seconds, the equation would work as follows:
200 x 5 = Y
1000 = Y
Putting equation
0 = -16t² + 36t + 4
<span>0 = -8t² + 18t + 2 ← Complete the square to solve </span>
<span>-8(t² - 9t/2) = -2 </span>
<span>8(t² - 9t/4 + 81/64) = 2 + 81/8 </span>
<span>8(t - 9/8)² = 97/8 </span>
<span>(t - 9/8)² = 97/64 </span>
<span>t -</span><span> (t = 0) </span>
<span> (h = 0) at: </span>
<span>t = (9 + √97)/8 ≅ 2.356 seconds
hope it helps</span>
I think the answer is d. -11
Explanation:
Replace the variable x with 3 in the expression.
f(3)=-2•3-5
Multiply -2 by 3
f(3)=-6 -5
Subtract 5 from -6
f(3)= -11
Then the answer should be -11.
