Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
So to add fractions they need to have a common denominator, which in this case is 24. then multiply 1 by 4 and 5 by 3 because whatever you multiply the denominator by you need to do the same to the numerator, which will get you 4/24+15/24 then you add across the numerators and you get 19/24
C. -5 + 9 = 22 + 9 - 7 is the answer.
This is because when solved it’s : -52 = 15 which is false therefore there’s no solution.
Not sure what you’re trying to find but here’s the simplified version:
-4<=2t+5<11
-9<=2t<6
-9/2<=t<3
