Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

Take positive value x. You get

2. According to the previous theorem,

Then

Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

This means that you cannot find solutions of this equation. Then CD≠2 cm.
We know the equation of a line is y=mx+b. We know the slope (m) is -2 and all we need is the intercept (b).
Since we know one point, we can plug in 6 for x and 3 for y (along with -2 for m) in our equation and then solve for b.
3= -2*6 + b
3= -12 + b
15 = b
Since we now know the intercept we can now write our equation:
y= -2x + 15
Answer:
(x, y) = (-3, 2)
Step-by-step explanation:
Put the given value of y into the equation and solve for x.
... 7·2 +3x = 5
... 3x = -9 . . . . . . subtract 14
... x = -3 . . . . . . . divide by the x-coefficient
The solution (x, y) is (-3, 2).