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2 years ago

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At the end of a 30-question round, you’ve gotten 23 questions correct and only 7 wrong, giving you a total score of 94 points. Y

our friend, on the other hand, got 16 questions correct and 14 wrong for a total score of 38 points. Create a system of equations to represent this situation. Let x represent the amount of points received for a correct answer and y represent the amount of points for an incorrect answer.

2 answers:

natulia [17]2 years ago

3 0

Answer:

Hence, the system of equations that is used to represent the situation is:

23x+7y=94-----(1)

16x+14y=38------(2)

Step-by-step explanation:

Let x represent the amount of points received for a correct answer and y represent the amount of points for an incorrect answer.

You’ve gotten 23 questions correct and only 7 wrong,giving you a total score of 94 points.

So, the equation formed is:

23x+7y=94

Your friend, on the other hand, got 16 questions correct and 14 wrong for a total score of 38 points.

So, the equation formed is:

16x+14y=38

Hence, the system of equations that is used to represent the situation is:

23x+7y=94-----(1)

16x+14y=38------(2)

motikmotik2 years ago

3 0

Answer:

23x+7y=94-----(1)

16x+14y=38------(2)

Step-by-step explanation:

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What additional information could be used to prove ΔABC ≅ ΔMQR using SAS? Select two options. m∠A = 64° and AB = MQ = 31 cm CB =

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Answer:

m∠R = 60° and AB ≅ MQ

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Step-by-step explanation:

Given data :

Prove ΔABC ≅ ΔMQR using SAS

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2 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

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Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

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