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ruslelena [56]
3 years ago
8

How do you know if two lines are parallel?

Mathematics
2 answers:
GalinKa [24]3 years ago
4 0
The lines never intersect or touch should be the answer.

Hope this helps/works.
slavikrds [6]3 years ago
4 0
To know if two lines are parallel they have to have the same slope
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Miriams house has a markey value of 125,000. The tax accessory evaluated her property tax rate to be 42%. What is the assessed v
MakcuM [25]
If you use the formula it states Assessed Value = Market Value x Rate.
Assessed value = 125000
Rate = 42In addition to the rate, you must divide 42 by 100, which makes .42 then add 1.
42/100 = 0.42 + 1 = 1.42
125000(1.42) = 177500
$177,500 is Miriam's assessed value of her house.

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Write the equation in slope-intercept form. Then find the slope and y-intercept of the line.
MAXImum [283]

Answer:

y = -3x + 6

Step-by-step explanation:

To make this in slope intercept form, you need to use one step called inverse operation, all that is, is subtracting the 3x from both sides, which will eliminate the 3x on the left and add a negative 3x on the right

8 0
3 years ago
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

f(x) = \dfrac{2}{x - 1} + 4

From the given function, we have;

When x = 1, the denominator of the fraction, \dfrac{2}{x - 1}, which is (x - 1) = 0, and the function becomes, \dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as <em>x</em> increases, the fraction \dfrac{2}{x - 1} tends to 0, therefore as x increases, we have;

\lim_  {x \to \infty}  \dfrac{2}{(x - 1)} \to 0, and \  \dfrac{2}{(x - 1)}  + 4 \to 4

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, \dfrac{2}{0 - 1} + 4 = 2. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

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3 years ago
What is the answer to y=-0.5(0)+2
Korolek [52]
The answer is: Y= 2.
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3 years ago
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