Answer:
all FALSE except 3 and 4
Step-by-step explanation:
Hope this helps
Answer:
<h2>1.84feet</h2>
Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range 
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,

Squaring both sides we have;

The arrow will hit the target 1.84feet below the bullseye.
<h2>
Answer:</h2>
y = 2
<h2>
Step-by-step explanation:</h2>
To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.
<h3>Finding the Slope of the line:</h3>


<u>Substitute the coordinates of the given points:</u>

<u>Simplify the equation to determine the slope:</u>

∴ 0 divided by ANY number is ALWAYS 0.

<h3>Finding the equation of the line:</h3>
Point slope form formula: y - y₁ = m(x - x₁)
- x₁ and y₁ are the coordinates of any given point.
- m is the slope
<u>Substitute the values in the point slope form:</u>


<u>Simplify the equation to determine the equation of the line:</u>
∴ Any number multiplied by 0 is 0.



Thus, the equation of the line is y = 2.
Here, z = kx
k = z/x
k = 228/12
k = 19
So, when x = 18,
z = 19 * 18
z = 342
In short, Your Answer would be: 342
Hope this helps!
Answer:
36 cm2
Step-by-step explanation:
tep-by-Step:
Start with the formula:
Area = a2
Don't forget: a2 = a × a (a squared).
Substitute the side length into the formula. In our example, a = 6.
Area = 6^2 = 6 × 6 = 36 cm2
Answer:
The area of the square with sides of length 6 cm is 36 cm2.