Given f (x) = 2x, g(x) = x + 4, and h(x) = 5 – x3, find (f + g)(2), (h – g)(2), (f × h)(2),
Answer:
The difference of two numbers is 5:
x - y = 5
Their quotient is 2:
x/y = 2
Since x/y = 2 then x = 2y
Substituting into x-y=5 gives:
2y - y = 5
y = 5
x = 2y = 2(5) = 10
Your numbers are 10 and 5
Hope it helps
Step-by-step explanation:
Answer:
A, C & D
Step-by-step explanation:
A) 1 + 3x = -x + 4 {subtract 1}
1 + 3x -1 = -x + 4 - 1
3x = -x + 3 {add x}
3x + x = -x + 3 + x
4x = 3 {Divide by 4}
4x/x = 3/4
x = 3/4
C) 1 + 3x = -x +4 {Add x}
1+ 3x + x = - x +4 + x
1 + 4x = 4 {subtract 1}
4x = 4 - 1
4x = 3 {Divide by 4}
D) 1 + 3x = -x + 4 { Subtract 3x}
1 = -x + 4 -3x
1 = -4x + 4 Subtract 4}
1 - 4 = -4x
-3 = -4x {Divide by -4}
-3/-4 = x
x = 3/4
x = 3/4
Answer:
use the division to see the the size of he pool it is 6.3
Step-by-step explanation:
