To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
Answer:
Plain is $7 and Holiday is $15
Step-by-step explanation:
Castel: 2p + 5h = 89
Kali: 9p + 10h = 213
Double Castel's: 4p + 10h = 178
Subtract fro Kali's 9p + 10h = 213
- 4p + 10h = 178
5p = 35
p = 7 Plain is $7
Substitute 7 into one of the equations and solve for h:
2(7) + 5h = 89
14 + 5h = 89
5h = 75
h = 15 Holiday is $15
Answer:
P=6x+8
A=2x^2+11x-21
Step-by-step explanation:
Perimeter:
P=2(x+7)+2(2x-3)
P=6x+8
Area:
A=(x+7)(2x-3)
A=2x^2+11x-21
Probably A, a plane
I hope this helps you! If it does, please rate as Brainliest :D
