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Natalka [10]
3 years ago
8

I need help solving these problems​

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0

QUESTION 1

4 {p}^{2}  =  2 \times 2\times  {p} \times p

QUESTION 2

39 {b}^{3}  {c}^{2}  = 3 \times 13 \times  {b} \times b \times b\times  {c} \times c

QUESTION 3

100 {x}^{3} y {z}^{2}  =  {2} \times 2 \times  {5} \times 5  \times  {x} \times x \times x\times y \times  {z} \times z

QUESTION 4

66 {d}^{4}  = 2 \times 3 \times 11 \times  {d} \times d \times d \times d

QUESTION 5

85 {x}^{2}  {y}^{2}  = 5 \times 17 \times  {x} \times x   \times {y} \times y

QUESTION 6

18xy = 2 \times  {3}^{2}  \times x \times y

36 {y}^{2}  =  {2}^{2} \times  {3}^{2}   \times  {y}^{2}

The greatest common factor is the product of the least powers of the common factors;

GCF=2 \times  {3}^{2}  \times y

GCF=18y

QUESTION 7

25mn =  {5}^{2}  \times m \times n

21m = 3 \times 7 \times m

GCF=m

QUESTION 8

15a = 3 \times 5 \times a

28a {b}^{2}  =  {2}^{2}  \times 7 \times a \times  {b}^{2}

GCF=a

QUESTION 9

24 {d}^{2}  =  {2}^{3}  \times 3 \times  {d}^{2}

30 {c}^{2} d = 2 \times 3 \times 5 \times d

GCF=2 \times 3 \times d

GCF=6d

QUESTION 10

20gh =  {2}^{2}  \times 5 \times g \times h

36 {g}^{2}  {h}^{2}  =  {2}^{2}  \times  {3}^{2}  \times  {g}^{2}  \times  {h}^{2}

GCF= {2}^{2}  \times g \times h

GCF=4gh

QUESTION 11

17 {c}^{3}  {d}^{2}  = 17 \times  {c}^{3}  \times  {d}^{2}

5 {c}^{2}  {d}^{2}  = 5 \times  {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}  \times  {d}^{2}

GCF= {c}^{2}{d}^{2}

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Oksi-84 [34.3K]

Answer:

reason

1. symmetrical property

sides can be interchanged and its still true

statement

1. if triangle kjm is congruent to klm

then klm is congruent to klm

reason

2. reflexive property

triangle is congruent to itself

statement

2. triangle kjm is congruent to triangle kjm

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3. transitive property

if the 1st 2 triangles are congruent to each other and congruent to a third

then the first triangle is congruent to the third triangle

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6 0
3 years ago
You have $90,000 for investment. You will invest S dollars in stocks and B dollars in bonds. You expect a 10% return on stocks a
SIZIF [17.4K]

The dollar amount for the return on stocks is $3375 and the dollar amount for the return on bonds is $1125.

Two equations can be derived from the question:

s + b = $90,000 equation 1

0.1s + 0.02b = $4500 equation two

$4500 = 0.05  x $90,000

The above equation is a simultaneous equation and it would be solved using the elimination method.

The following steps would be take to determine the value of b

Multiply equation 1 by 0.1

0.1s + 0.1b = 9000 equation 3

Subtract equation 2 from 3

0.08b = $4500

b = $56,250

The following step would be taken to determine the value of s

Substitute for b in equation 1

s + $56,250 = $90,000

$90,000 - $56,250 = s

s = $33,750

Dollar amount for the return on stocks = $33,750 x 0.1 = $3375

Dollar amount for the return on bonds = $56,250 x 0,02 = $1125

To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults

7 0
3 years ago
The quotient of 2 numbers is -3 and their difference is -16. What are the 2 numbers?​
n200080 [17]

Answer:

-24 / 8

= -3

8 - 24

= -16

so the 2 numbers are 8 and - 24

3 0
4 years ago
Wrie down the equation of the line that is parallel to 4x - 2y = 7 and passes through (9, -3) ​
EastWind [94]

Answer:

4x-2y =42 is the required equation

Step-by-step explanation:

given equation is,

4x-2y -7=0---------eqn1

parallel equation of given equation is

4x -2y+k =0-------eqn 2

now passing it through (9,-3), we get,

4×9 + 2×3 +k = 0

or,36+6+k =0

or,42+k =0

or, k= -42

putting the value of k in eqn2

4x-2y - 42=0

4x-2y = 42

4 0
3 years ago
In the figure above, what is the value of w?
Sholpan [36]
The answer would be c 110
7 0
3 years ago
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