Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
Answer:
48 to 32 8 to 4 4 to 2 24 to 16
Step-by-step explanation:
(4 – 2i)(6 + 2i)
FOIL
First : 4*6 =24
Outer: 4*2i = 8i
Inner: -2i* 6 = -12i
Last: -2i*2i = -4i^2 =-4(-1) =4
Add together
24+8i-12i+4
28-4i
Answer: 28-4i
Well I THINK triangle ABC is just a stretched out version of triangle DEF.
To find the area of a triangle, you multiply base and height, and divide by 2.
Area of DEF is 6, so that means that (4 * x)/2 = 6.
6*2 = 12....
4 * x = 12........
4 * 3 = 12.
x = 3.
Comparing DEF to ABC: ABC's base is 3 times as long as DEF's. So that means the height must be three times as long.
3*3 = 9.
(12 * 9)/2 =54
