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kogti [31]
3 years ago
14

What is the 8th term of the geometric sequence a2 = 20 and r = 5

Mathematics
1 answer:
algol [13]3 years ago
8 0

Answer:

8th term of geometric sequence is 312500

Step-by-step explanation:

 Given :  a_2=20 and common ratio (r) = 5

We have to find the 8th term of the geometric sequence whose a_2=20 and common ratio (r) = 5  

Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).

     a_n=ar^{n-1}  ......(1)

where  a_n  is nth term and a is first term.

For given sequence

a can be find using  a_2=20 and r =  5

Substitute in (1) , we get,

a_2=ar^{2-1}

\Rightarrow 20=a(5)  

\Rightarrow a=4

Thus, 8th term of the sequence denoted as  a_8

Substitute n= 8 in (1) ,  we get,

a_8=ar^{8-1} \\\\a_8=(4)r_{7} \\\\a_8=4(5)^7=4 \times 78125=312500

Thus 8th term of geometric sequence is 312500

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Answer:

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Step-by-step explanation:

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Next, the y-intercept is the point on the graph where it crosses the y-axis, and has the coordinates, (0, b). It is also the value of y when x = 0. Since you're given the y-intercept of -9, then that means that it is the y-coordinate of (0, <em>b</em>). So, it becomes (0, -9).

Now that we have our slope (<em>m </em>) = 1/5, and the y-intercept (<em>b </em>) = -9, we can write the equation of the line as:

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In the second equation, we have

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