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Mathematics

1 answer:

Stella [2.4K]3 years ago

8 0

Answer:

-1/x

Step-by-step explanation:

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Joe makes belts. He has 9 buckles. He uses 12 rivets on each of 4 belts and 15 rivets on each of 2 belts. He has 22 rivets left

Lerok [7]

Answers:

1. There are rivets on the belts.

2. Extra information given in the problem:

a. He has 9 buckles.

b. He has 22 rivets left over.

Solution:

1. Total rivets on the belts=(12 rivets/belt)(4 belts)+(15 rivets/belt)(2 belts)

Total rivets on the belts=48 rivets+30 rivets

Total rivets on the belts=78 rivets

2. The extra information given in the problem is the information that we didn't use to solve it. In this case:

a. He has 9 buckles.

b. He has 22 rivets left over.

4 0

3 years ago

What value of a make the equation 14-a=19-12

abruzzese [7]

$14-a=19-12\\14-a=7\\a=14-7\\a=7$

5 0

2 years ago

Read 2 more answers

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$