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Greeley [361]
3 years ago
5

According to a government commision, 70% of all the nation’s households have vcrs. In a random sample of 15 households, what is

the probability that exactly 10 have vcrs
Mathematics
1 answer:
anygoal [31]3 years ago
7 0

Answer:  P(10,15,0.7)=3003*0.7^10*0.3^5=approx  0.2061

Step-by-step explanation:

The required probability P(10,15,0.7)= C15 10 *p^10*q^(15-10) where

C15 10=  15 !/10!/5!= 11*12*13*14*15/(2*3*4*5)=11*12*13*14/(2*4)=11*3*13*7=

=77*39=3003

p=0.7    q=1-p =1-0.7= 0.3 (probability of not having vcrs)

So P(10,15,0.7)=3003*0.7^10*0.3^5=approx  0.2061

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What is 9\12 as a percent?​
dimulka [17.4K]

Answer:

75%

Step-by-step explanation:

9/12 =

9 ÷ 12 =

0.75

Which is 0.75= .75

so 75/100= 75%

<em>ZaZa Out-</em>

 

4 0
3 years ago
If the errors produced by a forecasting method for 3 observations are +3, +3, and −3, then what is the mean squared error?
KiRa [710]

Answer:

9

Step-by-step explanation:

The mean squared error (MSE)of a set of observations can be calculated using the formula :

(1/n)Σ(Actual values - predicted values)^2

Where n = number of observations

Steps :

Error values of each observation (difference between actual and predicted values) is squared.

Step 2:

The squared values are summed

Step 3:

The summation is the divided by the number of observations

The difference between the actual and predicted values is known as the ERROR.

(1/n)Σ(ERROR)^2

n = 3

Error = +3, +3, - 3

MSE = (1/3)Σ[(3)^2 + (3)^2 + (-3)^2]

MSE = (1/3) × [9 + 9 + 9]

MSE = (1/3) × 27

MSE = 9

5 0
3 years ago
Please answer this I give brainliest! :-) No responding fake answers, will be reported to the service:
Mrrafil [7]

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Step-by-step explanation:

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3 0
3 years ago
A number divided by 7 is 9
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5 0
3 years ago
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The Intelligence Quotient (IQ) test scores for adults are normally distributed with a population mean of 100 and a population st
adell [148]

Answer: 0.7471

Step-by-step explanation:

Given : The Intelligence Quotient (IQ) test scores for adults are normally distributed with a population mean of \mu=100 and a population standard deviation of \sigma=15.

Sample size = 50

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponding to x=98 will be:-

z=\dfrac{98-100}{\dfrac{15}{\sqrt{50}}}\approx-0.94

Z-value corresponding to x=103 will be:-

z=\dfrac{103-100}{\dfrac{15}{\sqrt{50}}}\approx1.41

Using the standard normal distribution table for z-scores, we have

P-value = P(98

Hence, the  probability we could select a sample of 50 adults and find that the mean of this sample is between 98 and 103 = 0.7471

8 0
4 years ago
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