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lesya [120]
3 years ago
11

One month ruby wokred 6 more hours than isaac and svetlana worked 4 times as many as ruby they together worked 126 hours how man

y hours did each person work
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0
R + R - 6 + 4R = 126
6R - 6 = 126
6R = 126 + 6
6R = 132
R = 132/6
R = 22 (hours Ruby worked)
I = R - 6
I = 22 - 6
I = 16 (hours Isaac worked)
S = 4R
S = 4(22)
S = 88 (hours Svetlana worked)

Finally, let's check our three answers to see if their sum is 126 (the given total of hours worked):
22 + 16 + 88 = 38 + 88 = 126


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Use set builder notation to give a description of each of these sets. a) {0,3,6,9,12} b) {−3,−2,−1,0,1,2,3} c) {m,n,o,p}
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Answer:

\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}\\\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}\\\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}

Step-by-step explanation:

The set is a well-defined collection of objects.

Set builder form describes the set by stating the property of each of its elements.

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\left \{ 0,3,6,9,12 \right \}=\left \{ x;x=3n\,,\,n\,\varepsilon \,W ;\,\,n\leq 4\right \}

W is a set of whole numbers.

b)

\left \{ -3,-2,-1,0,1,2,3 \right \}=\left \{ x;x=\pm n;\,\,n=0,1,2,3 \right \}

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\left \{ m,n,o,p \right \}=\left \{ x;x \,\,is\,\,an\,\,alphabet\,\,after\,\,l\,\,and\,\,before\,\,q \right \}

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the complete question in the attached figure


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Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

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Then the ones with no x:

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Lastly, divide

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Have a good day :)

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