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lesya [120]
3 years ago
11

One month ruby wokred 6 more hours than isaac and svetlana worked 4 times as many as ruby they together worked 126 hours how man

y hours did each person work
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0
R + R - 6 + 4R = 126
6R - 6 = 126
6R = 126 + 6
6R = 132
R = 132/6
R = 22 (hours Ruby worked)
I = R - 6
I = 22 - 6
I = 16 (hours Isaac worked)
S = 4R
S = 4(22)
S = 88 (hours Svetlana worked)

Finally, let's check our three answers to see if their sum is 126 (the given total of hours worked):
22 + 16 + 88 = 38 + 88 = 126


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I really need help with this question!
Bingel [31]
I would convert -2pi / 3 to degrees first by multiplying by 180degrees / pi. It equals 120 degrees.

120 degrees is in quadrant II, which is 90 degrees plus 30 degrees. It is 60 degrees from the 180 degrees. 
So the reference triangle you use is 60 degrees.
Cos60 = 0.5
sin60 = sqrt(3) /2

But in quadrant II the only trig ratio that's positive is sin; all others are negative. 
So cos120 = -0.5
sin60 = sqrt(3) /2

<span>Keeping in mind that points on unit circle are (cos, sin), the point is </span>(-0.5, <span>sqrt(3) /2).
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6 0
3 years ago
The table below shows some values of a linear function. What are the missing values
Black_prince [1.1K]

Answer:

C

Step-by-step explanation:

to get to 18 from 15, you add three.

You keep adding three to every number for the y values since it it a linear function. The x values went up by 1 and the y values went up by 3.

5 0
3 years ago
6+√-80 ?
erik [133]
The answers are
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2. B
3. C
5 0
3 years ago
Alvin has $760 less invested in 7% than he has at 5%. If his annual income from these two investments is $51.20, how much does h
kondor19780726 [428]

Answer:

Alvin invested $110 at rate of 7% and invested $870 at rate of 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem

Let

x------> the amount of money invested at rate of 5%

At rate of 7%

we have

t=1\ years\\ P=(x-\$760)\\r=0.07

At rate of 5%

we have

t=1\ years\\ P=x\\r=0.05

substitute in the formula

51.20=(x-760)(0.07*1)+(x)(0.05*1)

51.20=0.07x-53.2+0.05x

51.20+53.2=0.12x

x=104.4/0.12=\$870

therefore

Alvin invested ($870-$760)=$110 at rate of 7%

Alvin invested $870 at rate of 5%  

8 0
3 years ago
Add:<br> 130 + (-54) =<br> How do I solve it
Mazyrski [523]

130-54=76

You just need to know when there is +- you just subtract the numbers with the charge of the largest number

6 0
3 years ago
Read 2 more answers
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