Question

I got CONFUSED PLZ HELP?

Answer 1

Answer:

$x = \sqrt{48} \\\\x = \sqrt{63} \\\\x = \sqrt[3]{73}$

Step-by-step explanation:

$x^2 = 48\\x^2 = 63\\x^3 = 73$

Solve for x

Equation 1 ;

$x^2 =48\\\\Square\:root\:both\:sides\\\\\sqrt{x^2} =\sqrt{48} \\\\Simplified \:form;\\x =4\sqrt{3}$

Equation 2;

$x^2 =63\\\\Square\:root\:both\:sides\\\\\sqrt{x^2} =\sqrt{63} \\\\Simplified \:form;\\x =3\sqrt{7}$

Equation 3 ;

$x^3 =73\\\\Cube\:root\:both\:sides\\\\\sqrt[3]{x^3}= \sqrt[3]{73} \\\\x = \sqrt[3]{73}$

Answer 2

Answer:

A, B, F

Step-by-step explanation:

To solve this, you look at the powers of x and take either the square root (if it is to a power of 2) or the cube root (if a power of 3) of both sides to isolate x. For the first equation, you take the square root of 48, so A is correct. For the second one, you take the square root of 63, so B is correct. For the final equation, you take the cube root of 73, so F is correct.