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3 years ago

Katrina's weight is within 8 pounds of her ideal weight of 130 pounds. What is her range of weight?

Mathematics

2 answers:

IrinaK [193]3 years ago

5 0

Answer:

The Answer is b. 122 space greater or equal than space x space greater or equal than space 138

Step-by-step explanation:

her ideal weight of course being 112-128 lbs will ultimately make the change in variation of her divided mass to be less than 8 pounds as her ideal weight or over

bearhunter [10]3 years ago

3 0

B..... i think........

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NNADVOKAT [17]

The scale factor is 1.25, I believe

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3 years ago

If a binomial event has a probability of success of 0.4, how many successes would you expect out of 6000 trials?

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4 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

8 0

3 years ago

A scientist studying earth's rotation determines that a specific location on earth's equator travels about 40,000 kilometers in

Mama L [17]

Answer:

Step-by-step explanation:

Discussion

The first thing you have to do is convert km to miles

Formula

1 mile = 1.6 km

x mile = 40000 km Cross Multiply

Solution

1.6*x = 1 * 40000 Divide by 1.6

x = 40000/1.6

x = 25000 miles

Answer Part 1

The distance covered is 25000 miles

Discussion Part 2

That's the distance covered in a day. Now we need to convert that to speed. The time (in hours) for 1 day is 24 hours.

Givens

d = 25000 miles

t = 24 hours

s = ?

Solution

s = d/t

s = 25000 / 24

s = <u>1041.66 </u> miles per hour

Answer: 1041.66 is what is to be entered as your answer

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2 years ago

Lable point B at (2,-3/2)

otez555 [7]

A (-4, 3) quad ll b (2, 1) quad l c (5, 0) x-axis

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3 years ago