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Hunter-Best [27]
3 years ago
12

The following octagon is formed by removing four congruent triangles from a rectangle. What is the area of the rectangle?

Mathematics
2 answers:
zimovet [89]3 years ago
6 0

Answer:

A=60 cm^{2}

Step-by-step explanation:

The area of a rectangle is defined as

A=l \times w

Where l is the length and w is the width.

If you observe the given graph, you will find that the dimensions are

l=2+6+2=10cm

w=2+2+2=6cm

So, replacing these dimensions we have

A=10cm \times 6cm\\A=60 cm^{2}

Therefore, the right answer is the last choice, A=60 cm^{2}

prisoha [69]3 years ago
5 0
Area= length times width. 10×6 is 60. Answer is 60 cm^2
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A rectangular plot of land has an area 9/10 square mile.The length is 3/2miles whats the width
Georgia [21]
A = L * W
(9/10) = (3/2) * W
Divide both sides (3/2)
(9/10) / (3/2) = W
(9/10) * (2/3) = W
18/30 = W
6/10 = W
W = 3/5 mile
6 0
3 years ago
Read 2 more answers
F is a polynomial of degree 6. f has a root of multiplicity
frutty [35]

Answer:

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

Step-by-step explanation:

We have a 6th degree polynomial  f(x)

r = 3 is a root of f with multiplicity 2

r = 1 is a root of f with multiplicity 3

f(-5) = -29721.6

f(-10) = 0

Then:  f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)

f(-5) = a *  (-8)^2 *  (-6)^3  *  (5)  =  -29,721.6

a* (64) * (-216)* 5 = -29,721.6

-a*69,120 = -29,721.6

a =  -29,721.6/-69,120

a =  0.43

so

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

4 0
3 years ago
There are 60 students in a classroom, 50% of the students are
vivado [14]

Answer:

28

Step-by-step explanation:

If 50% of students are boys that means there are 30 boys and 30 girls. Then if   30% of boys are 10 and 60% of girls are 18. You add 18+10 and that gives you 28.

6 0
2 years ago
Could you help me again and explain how you do it please I will give you 50 points
Keith_Richards [23]

Answer:

9 meters sorry if thats wrong

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What is the equation of the line that passes through the points (-1, 7) and (2, 10) in Standard Form?
Usimov [2.4K]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{2-(-1)}\implies \cfrac{3}{2+1}\implies \cfrac{3}{3}\implies 1

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}

just to point something out, is none of the options, however -x + y = 8, is one, though improper.

3 0
2 years ago
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