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Hunter-Best [27]
3 years ago
12

The following octagon is formed by removing four congruent triangles from a rectangle. What is the area of the rectangle?

Mathematics
2 answers:
zimovet [89]3 years ago
6 0

Answer:

A=60 cm^{2}

Step-by-step explanation:

The area of a rectangle is defined as

A=l \times w

Where l is the length and w is the width.

If you observe the given graph, you will find that the dimensions are

l=2+6+2=10cm

w=2+2+2=6cm

So, replacing these dimensions we have

A=10cm \times 6cm\\A=60 cm^{2}

Therefore, the right answer is the last choice, A=60 cm^{2}

prisoha [69]3 years ago
5 0
Area= length times width. 10×6 is 60. Answer is 60 cm^2
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Which of the following are solutions to the equation below?
Dovator [93]

Answer:

Apply quaratic equation

6 0
2 years ago
!SUBSTITUTION METHOD!<br><br>6y - 5z = -8 <br>3z = -6 <br>4x - 3y - 2z= 21​
hichkok12 [17]

Answer:

<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>

Step-by-step explanation:

6y - 5z = -8 .......... Equation 1

3z = -6 ................... Equation 2

4x - 3y - 2z= 21...... Equation 3

<u>First solve for z in Equation 2</u>

That's

3z = - 6

Divide both sides by 3

<h3>z = - 2</h3>

Next substitute the value of z into Equation 1 in order to find y

We have

6y - 5(-2) = - 8

6y + 10 = - 8

6y = - 8 - 10

6y = - 18

Divide both sides by 6

<h3>y = - 3</h3>

Finally substitute the values of y and z into Equation 3 to find the value of x

That's

4x - 3(-3) - 2(-2) = 21

4x + 9 + 4 = 21

4x + 13 = 21

4x = 21 - 13

4x = 8

Divide both sides by 4

<h3>x = 2</h3>

So the solutions are

<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>

Hope this helps you

3 0
3 years ago
Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =
marissa [1.9K]
In Cartesian coordinates, the region is given by -3\le x\le3, -\sqrt{9-x^2}\le y\le\sqrt{9-x^2}, and -\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}. Converting to cylindrical coordinates, using

\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}

we get a Jacobian determinant of r, and the region is given in cylindrical coordinates by 0\le\theta\le2\pi, 0\le r\le3, and -\sqrt{16-r^2}\le z\le\sqrt{16-r^2}.

The volume is then

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3
6 0
2 years ago
Please Help Me On This
anastassius [24]

Answer:

X2 = (-2, 1), W2 = (-4, 1), Y2 = (4, -2), Z2 = (-3, 2)

Step-by-step explanation:

First, flip across the y-axis:

Coordinates: X1 = (2, -1), W1 = (4, -1), Y1 = (2, -4), and Z1 = (3, -2)

Then, rotate 180 degrees counterclockwise:

Coordinates: See above

5 0
3 years ago
A triangle has an angle that measures 10°. The other two angles are in a ratio of 3:14. What
ivann1987 [24]

Step-by-step explanation:

<h3>Need to FinD :</h3>

  • We have to find the measures of other two angles of triangle.

\red{\frak{Given}} \begin{cases} & \sf{The\ measure\ of\ one\ angle\ of\ traingle\ is\ {\pmb{\sf{10^{\circ}}}}.} \\ & \sf{The\ other\ two\ angles\ are\ in\ the\ ratio\ of\ {\pmb{\sf{3\ :\ 14}}}.} \end{cases}

We know that,

  • The other two angles of triangle are in the ratio of 3 : 14. So, let us consider the other two angles of the triangle be 3x and 14x.

Angle sum property,

  • The angle sum property of triangle states that the sum of interior angles of triangle is 180°. By using this property, we'll find the other two angles of the triangle.

\rule{200}{3}

\sf \dashrightarrow {10^{\circ}\ +\ 3x\ +\ 14x\ =\ 180^{\circ}} \\ \\ \\ \sf \dashrightarrow {10^{\circ}\ +\ 17x\ =\ 180^{\circ}} \\ \\ \\ \sf \dashrightarrow {17x\ =\ 180^{\circ}\ -\ 10^{\circ}} \\ \\ \\ \sf \dashrightarrow {17x\ =\ 170^{\circ}} \\ \\ \\ \sf \dashrightarrow {x\ =\ \dfrac{\cancel{170^{\circ}}}{\cancel{17}}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{x\ =\ 10^{\circ}.}}}}_{\sf \blue {\tiny{Value\ of\ x}}}}

∴ Hence, the value of x is 10°. Now, let us find out the other two angles of the triangle.

\rule{200}{3}

Second AnglE :

  • 3x
  • 3 × 10
  • 30°

∴ Hence, the measure of the second angle of triangle is 30°. Now, let us find out the third angle of triangle.

\rule{200}{3}

Third AnglE :

  • 14x
  • 14 × 10
  • 140°

∴ Hence, the measure of the third angle of the triangle is 140°.

5 0
2 years ago
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