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arlik [135]
3 years ago
11

Is each statement true for OA? Yes No KA ≈ MA L JKA ≈ L MLA L JKA ≈ L MLA

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0
Yes they are true .
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What are the potential solutions of log4x+log4(x+6)=2?
lions [1.4K]

The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
  • Power Rule for Logarithms - log_{b}(a^c)=c*log_{b}a

The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

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It cost Alexandra $9.90 to send 198 text messages. How many text messages did she send if she spent $2.35?
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Step-by-step explanation:

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This is really confusing. Thanks for helping.
Mandarinka [93]
Count change of signs to tell positive roots
then replace x with -x and evaluate, then count change in sign for negative roots


initially
+, -, -, +, +, -
3 changes
3 or 1 positive roots


replacing x with -x
-,-,+,+,-,-
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B is answer
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