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svlad2 [7]
3 years ago
15

Explain how to find the product 3^5 x 3^2 using rules for exponents.

Mathematics
1 answer:
AlekseyPX3 years ago
7 0

Step-by-step explanation:

\because \:  {a}^{m}  \times  {a}^{n}  =  {a}^{m + n}  \\  \\  \therefore \:  {3}^{5}  \times  {3}^{2}  =  {3}^{5 + 3}  =  {3}^{8}  = 6,561 \\

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Answer:

8*8 = 64

Step-by-step explanation:

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If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

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10x - 11 - 8x = 8x + 23 - 8x

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Add 11 to both sides

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Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

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2. m<MKL = 8x - 20

Plug in the value of x

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3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

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Y=-4x+3 is already in slope intercept form. Graphed it looks like this

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