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Pachacha [2.7K]
3 years ago
8

Pls i need help in this

Mathematics
1 answer:
timurjin [86]3 years ago
7 0
It’s a blank screen .. what’s the question ?
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PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie
Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

3 0
2 years ago
Simplify -3(x-4)+3(a-6)
Vilka [71]

Answer:

-3x+3a-6

Step-by-step explanation:

7 0
3 years ago
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Math C Peasha - Unit 5 Pythagorean Theorem and Irrational Numbers
vladimir2022 [97]
2 bc you can’t write it as a fraction
3 0
3 years ago
What 2 numbers can be added to make 16 as well as multiplied to make -36
Sladkaya [172]

Answer:

18 and -2

Step-by-step explanation:

Let x = 1st no.

y = 2nd no.

(1)    x + y = 16            (2)     xy = -36

           y = 16 - x                 x(16 - x) = -36

                                           16x - x^{2} = -36\\x^{2}  - 16x - 36 = 0\\

                                           (x - 18)(x + 2) = 0

                                               x = 18   or x = -2

          y = 16 - 18 = -2

         y = 16 -(- 2) = 16 + 2 - 18

The two numbers are 18 and -2

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3 years ago
Estimate the value of √2π/√5
Luba_88 [7]

Answer: 1.12099824328 or estimated is 1

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