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Jobisdone [24]
3 years ago
5

A box contains 9 green marbles and 17 white marbles. If the first marble chosen was a white marble, what is the probability of c

hoosing, without replacement, another white marble? Express your answer as a fraction or a decimal number rounded to four decimal places.
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

16/25

Step-by-step explanation:

Given

Number  of green marbles = 9

Number of White marbles = 17

Total number of marbles = 26

Probability of picking a white marble = 17/26

When a white marble is picked without replacement,

Probability of picking another white marble after first picking a white marble

= 16/25

= 0.64

This is because the total number of marbles would have reduced from 26 to 25 and the number of white marbles from 17 to 16.

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Answer:

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Step-by-step explanation:

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3 years ago
If function g has the factors (x - 7) and (x + 6), what are the zeros of function g?
SVEN [57.7K]

Answer:

7 and -6

Step-by-step explanation:

Given

Factors: (x - 7) and (x + 6)

Required

Determine the zeros

To do this, we simply equate the factors to 0

x - 7 = 0

x = 7

x + 6 = 0

x = -6

<em>So, the zeros are -7 and 6</em>

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2 years ago
How many numbers from 10 to 1,000 are palindroms
lakkis [162]
In fact from numbers 10 to 1000 
99 are palindromes
5 0
3 years ago
Given the factors, name the roots.<br> 3. f(x) = -3(2x – 5)(x + 2)
tekilochka [14]

Answer:

x = 5/2

or

x = -2

Step-by-step explanation:

recall that the roots of a function f(x) are basically the values of x that will make f(x) = 0,

we find these values of x by making f(x) = 0 and then solving the equation for x,

in our case,

f(x) = -3(2x – 5)(x + 2)

to find roots,

f(x) = 0

-3(2x – 5)(x + 2) = 0

Equating each factor = 0, the equation can be broken down into:

-3 = 0 (obviously not valid, hence we can ignore this)

or

(2x – 5) = 0     add 5 to both sides

2x = 5              divide both sides by 2

x = 5/2   ( Answer)

or

(x + 2) = 0      subtract 2 from both sides

x = -2 (Answer)

6 0
3 years ago
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MatroZZZ [7]
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