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Juliette [100K]
3 years ago
15

Look at this triangle work out length bc​

Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer:

perpendicular = 10.24 cm

Step-by-step explanation:

by pythagorus theorem,

h {}^{2}  = b {}^{2}  + h {}^{2}

( where, h = hypotenuse, b = base,

p = perpendicular )

so,

=》

13 {}^{2}  = 8 {}^{2}  + p {}^{2}

=》

169 = 64 + p {}^{2}

=》

169 - 64 = p {}^{2}

=》

p =  \sqrt{105}

perpendicular = 10.24 ( root 105 )

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2. Write a rule for the translation of ABC to A A'B'C'.<br> 12<br> B<br> 12
adell [148]

Answer:

I think its b

i hope you pass

8 0
3 years ago
Ms. taylor bought a water tube to pull behind her boat. the tube cost $87.00 and 9% sales tax was added at the register. ms.tayl
zhuklara [117]
Work out 9% of $87.00 then add theat to the $87.00 that will be the total cost. find how much cash she gave the cashier and then minus the total cost from that to find the change she got.
6 0
3 years ago
If f(x)=x+8 and g(x)=-4x-3 find (f+g)(x)
nydimaria [60]

Answer:

for this case we have the following functions:

f (x) = x + 8

g (x) = -4x - 3

Subtracting the functions we have:

(f - g) (x) = f (x) - g (x)

(f - g) (x) = (x + 8) - (-4x - 3)

Rewriting:

(f - g) (x) = x + 8 + 4x + 3

(f - g) (x) = 5x + 11

Answer:

D. (f - g) (x) = 5x + 11

7 0
3 years ago
Two drivers are exploring the bottom of a trench in the Pacific Ocean. Dominic is at 175 feet below the surface of the ocean and
mestny [16]

\huge\boxed{\text{Dominic}}

In this problem, 0 represents the sea level. Since Dominic is 175 feet below the surface (sea level), his current location is at -175 feet.

The same concept can be applied to Karen, who is at -138 feet.

We need to find who is lower, or farther below 0. This means the answer is \boxed{\text{Dominic}}.

7 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
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