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FinnZ [79.3K]
3 years ago
11

Find the annual percentage yield​ (APY) in the following situation. A bank offers an APR of 4.4​% compounded daily. The annual p

ercentage yield is (blank) %
Mathematics
2 answers:
marta [7]3 years ago
8 0

\bf ~~~~~~ \textit{Annual Yield Formula} \\\\ ~~~~~~~~~~~~ \left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily then 365} \end{array}\dotfill &365 \end{cases} \\\\\\ \left(1+\frac{0.044}{365}\right)^{365}-1~~ \approx 0.0449796\implies \stackrel{\textit{rounded up}}{0.045}\implies \stackrel{\textit{to percent}~\hfill }{0.045\cdot 100\implies 4.5}

fiasKO [112]3 years ago
7 0

Step-by-step answer:

APY (annual percentage yield) is the amount of interest in percent one would actually earn by investing a sum of money in a year.

It takes into account the interest rate expressed in any particular form, and the compounding period.

In the current market, most interest rates (for example, credit cards) are expressed in APR (Annual percentage rate) which is an underestimate of the actual amount to be paid, by NOT taking into account the compounding period, monthly (instead of annually) most of the time.  The shorter compounding period increases the APY.

Here the APR is 4.4%.  to take into account the compounding period, we divide the interest rate by 12 to give the monthly rate, 4.4%/12=0.044/12.

This rate will then be compounded 12 times to give the APY, or the future value after 12 months.

Future value = (1+0.044/12)^12 = 1.044898

Therefore the APY is 1.044898 less initial deposit, or

1.044898-1 = 0.044898, or 4.4898%, or 4.49% (rounded to 2 decimal places)

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4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513
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Answer:

Part 4) sin(\theta)=\frac{12}{13}

Part 10) The angle of elevation is 40.36\°

Part 11) The angle of depression is 78.61\°

Part 12) arcsin(0.5)=30\°  or arcsin(0.5)=150\°

Part 13) -45\°  or 225\°

Step-by-step explanation:

Part 4) we have that

cos(\theta)=-\frac{5}{13}

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

sin^{2}(\theta)+ cos^{2}(\theta)=1

substitute the given value

sin^{2}(\theta)+(-\frac{5}{13})^{2}=1

sin^{2}(\theta)+(\frac{25}{169})=1

sin^{2}(\theta)=1-(\frac{25}{169})  

sin^{2}(\theta)=(\frac{144}{169})

sin(\theta)=\frac{12}{13}

Part 10)

Let

\theta ----> angle of elevation

we know that

tan(\theta)=\frac{85}{100} ----> opposite side angle theta divided by adjacent side angle theta

\theta=arctan(\frac{85}{100})=40.36\°

Part 11)

Let

\theta ----> angle of depression

we know that

sin(\theta)=\frac{5,389-2,405}{3,044} ----> opposite side angle theta divided by hypotenuse

sin(\theta)=\frac{2,984}{3,044}

\theta=arcsin(\frac{2,984}{3,044})=78.61\°

Part 12) What is the exact value of arcsin(0.5)?

Remember that

sin(30\°)=0.5

therefore

arcsin(0.5) -----> has two solutions

arcsin(0.5)=30\° ----> I Quadrant

or

arcsin(0.5)=180\°-30\°=150\° ----> II Quadrant

Part 13) What is the exact value of arcsin(-\frac{\sqrt{2}}{2})

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

sin(45\°)=\frac{\sqrt{2}}{2}

therefore

arcsin(-\frac{\sqrt{2}}{2}) ----> has two solutions

arcsin(-\frac{\sqrt{2}}{2})=-45\° ----> IV Quadrant

or

arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\° ----> III Quadrant

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