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Galina-37 [17]
3 years ago
14

Which of the following is the surface area of the right cylinder below?

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer: Option A.

Step-by-step explanation:

You need to use this formula for calculate the surface area of the right cylinder:

SA=2\pi r^2+2\pi rh

Where "r" is the radius and "h" is the height.

You can identify in the figure that:

r=8units\\h=3units

Knowing this, you can substitute these values into the formula SA=2\pi r^2+2\pi rh, therefore you get that the surface area of this right cylinder is:

SA=2\pi (8units)^2+2\pi (8units)(3units)

SA=176\pi\ units^2

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Answer:

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Step-by-step explanation:

You have 32 coins in your pocket consisting of nickels and quarters with a total value of $5.40

How many nickels and quarters do you have?

Step 1: Setup Coin Value and Coin Total Equation:

Coin Value Equation → 0.05n + 0.25q = $5.40 where n = nickels and q = quarters

Coin Total Equation → n + q = 32

Step 2: Rearrange Coin Total Equation in terms of nickels (n)

n = 32 - q ← Revised Coin Total Equation

Step 3: Plug in our Revised Coin Total Equation for n into our Coin Value Equation:

0.05(32 - q) + 0.25q = $5.40

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1.6 + (0.25 - 0.05)q = $5.40

1.6 + 0.2q = $5.40

Step 4: Subtract 1.6 from each side of the equation to isolate q

1.6 - 1.6 + 0.2q = $5.40 - 1.6

0.2q = 3.8

Step 5: Divide each side of the equation by 0.2 to isolate q

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Step 6: Using our value for q, Solve for n using our Coin Total Equation:

n + 19 = 32

Subtracting 19 from both sides, we get n + 19 - 19 = 32 - 19

n = 13

Summarizing our word problem, we see that 19 quarters and 13 nickels adds up to $5.40

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